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3 years ago

Properties of interger Exponent

Mathematics

1 answer:

liraira [26]3 years ago

4 0

Answer:

<em><u>Answer is below</u></em>

Step-by-step explanation:

10^0

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4. The sum of Mr. and Mrs. Bergen's ages is 100. The difference between their ages is 10. How old are Mr. and Mrs. Bergen?

alex41 [277]

100-10=90

90÷2=45

Mr Bergen's age=45+10

=55 years old

Mrs Bergen's age=45 years old

8 0

3 years ago

Jan bought 6 cookies and 4 doughnuts for 3.50. Tom bought 12 cookies and 5 doughnuts got 5.23. Write and solve a system of equat

iren2701 [21]

0.19 for one cookie and 0.59 for one doughnut

x for how much one cookie costs and y for how much one doughnut costs
6x+4y=3.5
12x+5y=5.23

solve by substitution: (elimination would work too)
4y=3.5-6x
y=0.875-1.5x
12x+5(0.875-1.5x)=5.23
12x+4.375x-7.5x=5.23
4.5x=0.855
x=0.19
now use x to solve for y:
6(0.19)+4y=3.5
1.14+4y=3.5
2.36=4y
y=0.59

Check the work: 6(0.19)+4(0.59)=3.5

4 0

3 years ago

1.Solve for x (3.8,4.8,5.8,6.8)

vodomira [7]

6.8 is what i got for the answer

7 0

3 years ago

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

6 0

3 years ago

A group of friends are playing a game in which they roll a number cubed numbered 1 to 6 and flip a coin. The friend that rolls t

Ghella [55]

Answer:

A. The probability is 1/12. B. The probability is 1/10

Step-by-step explanation:

8 0

3 years ago