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inessss [21]
3 years ago
8

A 6-car monorail train can carry 78 people.If the train makes 99 trips during the day,what is the greatest number of people the

train can carry in one day?
A.177
B.7,524
C.7623
D.7,722
Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0
If the train can carry 78  people and it makess 99 trips,
the greatest number of people will be 
78*99= 7722
sergij07 [2.7K]3 years ago
5 0

Answer:

D.7,722

Step-by-step explanation:

We have been given that a 6-car monorail train can carry 78 people. The train makes 99 trips during the day. We are asked to find the greatest number of people the train can carry in one day.

The greatest number of people the train can carry in one day will be equal to number of trips times the total number of people that train can carry in each trip.

\text{The greatest number of people the train can carry in one day}=78\times 99

\text{The greatest number of people the train can carry in one day}=7722

Therefore, the train can carry at-most 7722 people in one day.

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The average score of all golfers for a particular course has a mean of 71 and a standard deviation of 3. Suppose 36 golfers play
Zielflug [23.3K]

Answer:

.0228

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 71, \sigma = 3, n = 36, s = \frac{3}{\sqrt{36}} = 0.5

Find the probability that the average score of the 36 golfers exceeded 72.

This is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{72 - 71}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

7 0
3 years ago
Each large rectangle below represents one whole. What percent is represented by the shaded area?​
Montano1993 [528]

Answer:

180%

Step-by-step explanation:

It is 180% because one rectangle is fully shaded which means that is 100%. THe other one is 4/5 of the way shaded or 80% shaded. So add and you get 180%

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3 years ago
Clayton and Timothy took different sections of Introduction to Economics. Each section had a different final exam. Timothy score
Andrews [41]

Answer: Fourth option is correct.

Step-by-step explanation:

Since we have given that

Timothy scored 83 out of 100.

His percentile rank in his class = 72

Clayton scored 85 out of 100.

His percentile rank in his class = 70.

Since Clayton's percentile rank is lower than Timothy's rank.

So, Timothy performed better with respect to the rest of the students in the class.

Hence, Timothy as his percentile score is higher.

Therefore, Fourth option is correct.

5 0
3 years ago
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