The length of the 2D cross-section = 22cm
Breadth of 2D cross-section = 12cm
Since it's inside a rectangular prism, it's area will be given by the formula of area of a rectangle.
→ Area of 2D cross-section = 22×12 = 264 cm²
Since the two equations equal y, set them equal to each other.
x-1=-2x+5
From there, solve for x.
First get x on one side, by using the addition property of equality.
x-1=-2x+5
3x-1=5
Isolate x by adding 1.
3x=6
Lastly get x all by itself by dividing each side by 3.
x=2
You can now substitute your x-value, 2, into one of the equations (or both, if you wish; either one will result in the same answer.)
y=x-1
y=2-1
y=1
OR
y=-2x+5
y=-2(2)+5
y=-4+5
y=1
Final answer:
x=2 and y=1
Any questions or anything you would like me to clarify, feel free to ask :)
Answer:
Latter C.
Step-by-step explanation:
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Answer:
Let height be h
Base be B
thereforeNew area=(base+1)(hieght+1)
=(b+1)(h+1)
=bh+h+b+1
