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igomit [66]
3 years ago
14

Mutiply 4y-4w^8-3y^5w^3

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

Answer:

48y⁶w¹¹

Step-by-step explanation:

[-3y⁵][4y] → -12y⁶

×

[w³][-4w⁸] → -4w¹¹

______

48y⁶w¹¹

I am joyous to assist you anytime.

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Let A= {1, 3, 6, 8, 9} B= {2, 5, 6, 7, 8} C= {1, 4, 6, 7, 8, 9} and D= {1,2}
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Answer with Step-by-step explanation:

Let A= {1, 3, 6, 8, 9}

B= {2, 5, 6, 7, 8}

C= {1, 4, 6, 7, 8, 9}

and D= {1,2}

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A∪B={1,2,3,5,6,7,8,9}    (union of two sets is the set of element which are in any one of the two sets or in both)

(A∪B)∩C ={1,6,7,8,9}   (intersection of two sets are the set of elements which are in both the sets)

Calculate P(D), i.e. power set  of D

P(D)={Ф,{1},{2},{1,2}}   (Power set of any set is the collection of all the subsets of that set)

Is (A ∩ B) ⊆C? Why or why not?

A∩B={6,8}⊆{1, 4, 6, 7, 8, 9} =C

Hence, (A ∩ B) ⊆C

What is (B ∩ C) × {1,2}?

B∩C={6,7,8}

(B ∩ C) × {1,2}={6,7,8} × {1,2}

                     ={(6,1),(6,2),(7,1),(7,2),(8,1),(8,2)}

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Read 2 more answers
6- 6x^2- 3x = 0 solve
VARVARA [1.3K]

Answer:

The solutions are x=\frac{3)+\sqrt{153} }{-12}, x=\frac{3)-\sqrt{153} }{-12}

If you need to have them in a decimal form rounded to 3 decimals, the answers would be x=-1.281, x=0.781

Step-by-step explanation:

We are given the equation 6-6x^2-3x=0

The first thing that can be done is to rearrange the terms so that they are in descending order of power. This makes it easier to work with

This gives us -6x^2-3x+6=0

To find the solutions to this equation, we can use the quadratic formula, which will tell us that the solutions are equal to \frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

From our equation, we can gather that a=-6, b=-3, c=6

Now that we have our variables, we can plug them into the quadratic formula to get our solutions.

\frac{-(-3)+\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)+\sqrt{9+144} }{-12}\\\\\frac{3)+\sqrt{153} }{-12}

And now for our second equation

\frac{-(-3)-\sqrt{(-3)^2-4(-6)(6)} }{2(-6)}\\\\\frac{3)-\sqrt{9+144} }{-12}\\\\\frac{3)-\sqrt{153} }{-12}

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3 years ago
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