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DiKsa [7]
3 years ago
6

There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot

plots below.
Number of Students in Each Class at Poplar Middle School




Number of Students in Each Class at Oak Middle School



Which statement correctly compares the mean number of students for the data in the plots?
There are about 2 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.
There are about 5 more students in each class at Poplar Middle School than at Oak Middle School.
There are about 5 more students in each class at Oak Middle School than at Poplar Middle School.
Mark this and return

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0

Answer:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

The rest of the question is the attached figure.

It is required to compare between the mean number of students for the data in the plots.

The mean is sum of all data divided by the number of data.

The data set of Poplar Middle School:

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

So, The mean = 435/20 = 21.75

<u>The data set of Oak Middle School:</u>

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

So, The mean = 483/20 = 24.15

The difference in mean = 24.15 - 21.75 = 2.4

So, the correct statement is:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

aleksandrvk [35]3 years ago
4 0

Answer:

its There are about 2 more students in each class at Oak Middle School than at Poplar Middle School. aka B.

Step-by-step explanation:

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liubo4ka [24]

Answer:

Attached below

Step-by-step explanation:

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8 0
3 years ago
Tiara attended 12 piano classes in four weeks. If she attended the same number of classes each week, which equation can be used
skelet666 [1.2K]

Answer:

C

Step-by-step explanation:

Because i'm smart and did the math.

5 0
3 years ago
Please help, no links. PLEASE!!!!
notka56 [123]

There is a thousand answer to this problem.

Let's do the simplest one here.

f(x) or y = x - 1

f(x) or y = x + 1

f(x) or y = -x

Wait, would this count as a solution? : See the second attachment

8 0
2 years ago
Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
Read 2 more answers
Amir evaluated 5x - (x + 3)2 for x = 2, as shown. Describe Amir's mistake and find the correct answer. 5(2) - (2 + 3)2 = 10 + (-
Korvikt [17]

5 \times 2 - (2 + 3) \times 2 = 10 - 5 \times 2 = 10 - 10 = 0
7 0
3 years ago
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