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3 years ago

Assuming that one-pint is equal to 473 ml, how many pints can be found in 3 liters?

1 answer:

4 0

Given that 1 pint is equal to 437 ml
and 1000 ml=1 liter
then
1 pint =(437/1000) liters
simplifying we get:
1 pint= 0.437 liters
thus amount of pints in 4 liters will be:
4/0.473
=8.45666586
~8.5 pints

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makvit [3.9K]

Answer:

I think it's 1,125 and 4485

Step-by-step explanation:

25x13x3

115x13x3

3 0

3 years ago

Need asap!!!!!!!!!!!

katrin2010 [14]

Answer:

50 J

Step-by-step explanation:

According to energy conservative law energy can not be destroyed. So as the potential energy has been decreased to 50 J, the decreased amount has become kinetic energy.

100 - 50 = 50

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2 years ago

Consider the line shown on the graph. Enter the

Semenov [28]

<h2>Solution -</h2>

From the graph, we concluded that line passes through the points (0, 3) and (1, 4) respectively.

So, slope of the line (m) passing through the points (a, b) and (c, d) is

m = d - b/ c - a

<h3>So, on substituting the values, we get </h3>

m = 4 - 3 / 1 - 0 = 1/1 = 1

Also, line makes an intercept of 3 units in positive direction of y - axis.

So, c = 3

<h3>So, Equation of line is given by</h3>

y = mx + c

y = 1 × x + 3

<h3>Alternative Method :-</h3>

We know, Equation of line passing through the points (a,b) and (c, d) is given by

y - b = d - b / c - a (x - a)

a = 0

b = 3

c = 1

d = 4

<h3>So, on substituting these values in above result, we get :-</h3>

y - 3 = 4 - 3 /1 - 0 ( x - 0 )

y - 3 = 1/1 ( x - 0 )

y - 3 = x

<h3>Different forms of equations of a straight line :-</h3>

1. Equations of horizontal and vertical lines

Equation of line parallel to x - axis passes through the point (a, b) is y = b.

Equation of line parallel to y - axis passes through the point (a, b) is x = a.

<h3>2. Point-slope form equation of line</h3>

Equation of line passing through the point (a, b) having slope m isy - b = m(x - a)

<h3>3. Slope-intercept form equation of line</h3>

Equation of line which makes an intercept of c units on y axis and having slope m is y = mx + c.

<h3>4. Intercept Form of Line</h3>

Equation of line which makes an intercept of a and b units on x - axis and y axis respectively is x/a + y/b = 1.

<h3>5. Normal form of Line</h3>

Equation of line which is at a distance of p units from the origin and perpendicular makes an angle B with the positive X-axis is x cosB + y sinB = p.

<h2 />

8 0

2 years ago

Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r

erastova [34]

Answer:

The probability is $\frac{56!}{64!}$

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, $64 \choose 8 .$

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function $f : A \rightarrow A ,$ with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

$\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}$