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S_A_V [24]
3 years ago
10

Clark wants to figure out how many pens to order for the office there 48 workers and he needs to order one pen for each worker h

e knows that for every six people who prefer red door 6 prefer blue how many blue pens should he order
Mathematics
1 answer:
lakkis [162]3 years ago
5 0
Six times eight = forty-eight
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Radius and diameter ​
Galina-37 [17]

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diameter = 13 cm

radius =13/2=6.5cm

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WILL NAME BRAINLIST!!
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Step-by-step explanation:

The fourth graph makes sense, and follows Deepak's equation. To check if a graph follows an equation, all you have to do is substitute the values of x and y into the equation and see if they follow the equation.

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3 years ago
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A new patio is in the shape of a square. On a scale drawing, the vertices of the patio's coordinates are: (6,1.5), (6,-5.5), (-1
Shkiper50 [21]
Seven units long. The distance between 2 sides, in this example is 6, and -1. The distance between 6 and -1 is 7, so when you add units, you get 7 units.
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2 years ago
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(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).
frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0
1 year ago
Building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18 \pi18π18, pi m
Ksivusya [100]

the area A of the cross section of the column is (81\pi )m^2 .

<u>Step-by-step explanation:</u>

Here we have , building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18π, pi meters. We need to find What is the area A of the cross section of the column .Let's find out:

We know that  , Circumference of circle = 2\pi r

⇒ Circumference = 2\pi r

⇒ 18\pi= 2\pi r

⇒ \frac{18\pi}{2\pi }= \frac{2\pi r}{2\pi }

⇒ \frac{18\pi}{2\pi }=r

⇒ r=9

We know that area of circle = \pi r^2

⇒ Area= \pi r^2

⇒ Area= \pi 9^2

⇒ Area= 81\pi

Therefore , the area A of the cross section of the column is (81\pi )m^2 .

3 0
2 years ago
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