The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

Question

zysi [14]

2 years ago

6

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

able below. What is the justification for the 5th statement

Mathematics

2 answers:

ehidna [41] · Answer 1 · 2022-04-23T01:26:32+03:00

ehidna [41]2 years ago

6 0

Answer:

for anyone wondering, i got distance formula for sure. if you didn't, then read the question because you probably read it wrong.

Step-by-step explanation:

AURORKA [14] · Answer 2 · 2022-04-23T00:23:39+03:00

<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.