Question

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the table below. What is the justification for the 5th statement

Answer 1

Answer:

for anyone wondering, i got distance formula for sure. if you didn't, then read the question because you probably read it wrong.

Step-by-step explanation:

Answer 2

Answer:

D. Distance formula

Step-by-step explanation:

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

The distance form $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ whose justification is the Distance Formula.

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.