All categories

3 years ago

What is the sum of the exterior angle measures for an irregular convex hexagonal?

Mathematics

1 answer:

IceJOKER [234]3 years ago

3 0

I think that the answer is A.

You might be interested in

Please help thank you

Citrus2011 [14]

Answer:

8000

Step-by-step explanation:

It's the only number missing from the answer to arrive at the answer itself :)

5 0

3 years ago

Read 2 more answers

A: A behavior that does not depend on experience

Rashid [163]

Answer:

A. Innate

B. Estivation

C. Territory

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A house worth $180,000 has a coinsurance clause of 75 percent. The owners insure the property for $101,250. They then have a los

Bess [88]

Answer:

$37,500

Step-by-step explanation:

We have been given that a house worth $180,000 has a coinsurance clause of 75 percent. The owners insure the property for $101,250. They then have a loss that results in a $50,000 claim.

We will use loss settlement formula to solve our given problem.

$\text{Loss settlement}=\frac{\text{Loss}\times\text{Limit of insurance}}{\text{Actual cash value}\times \text{Coinsurance}\%}$

Upon substituting our given values, we will get:

$\text{Loss settlement}=\frac{\$50,000\times\$101,250}{\$180,000\times 75\%}$

$\text{Loss settlement}=\frac{\$50,000\times\$101,250}{\$180,000\times 0.75}$

$\text{Loss settlement}=\frac{\$5,062,500,000}{\$135,000}$

$\text{Loss settlement}=\$37,500$

Therefore, they will receive $37,500 from insurance.

5 0

3 years ago

What is the quotient and remainder of (4x^3-3x^2+x+7)/(x-2)

viva [34]

Answer:

4x^2+11x+23 r53

Step-by-step explanation:

4x^3-3x^2+x+7 / x-2

2 | 4 -3 1 7

8 22 46

___________

4 11 23 53

This means 4x^2+11x+23 with a remainder of 53

7 0

3 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

4 0

4 years ago