What is the sum of the exterior angle measures for an irregular convex hexagonal?
1 answer:
You might be interested in
Answer:
78.42
Step-by-step explanation:
Area of 360 - 80 degree region.
You need to find out the region of the major arc where the circle is almost complete. The area left over will be calculated later
Angle = 360 -80
Angle = 280 degrees.
Area =
Area =
Area = 23800/360
Area = 66.11
Area of the Triangle with sides of 5 cm each
Here's where I get into a bit of trouble. I have to assume you know some trig.
Find the height
Cos(40) = The height / the hypotenuse
Cos(40) = h/5
0.7760 = h/5
h = 0.7760*5
h = 3.830
Find 1/2 the base (the chord of the circle)
Sin(40) = 1/2 base / hypotenuse
Sin(40) = 1/2 b / 5 Multiply both sides by 5
1/2 b = 5*sin(40) Find the sin(40)
1/2 b = 5*.6428 Combine the right
1/2 b = 3.139 multiply by 2
b = 6.4278
Find the area of the triangle
Area = 1/2 b * h
b = 6.4278
h = 3.830
Area = 1/2 * 6.4278*3.830
Area = 12.31 cm^2
Total Area
12.31 + 66.11 = 78.42