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koban [17]
3 years ago
9

Melanie uses an old compact disk to store her company's contract documents. She finds out that she cannot access any documents b

ecause the compact disk is not compatible with the computer devices in her company. What type of risk led to this complication? Risk hampered Melanie's work.
Computers and Technology
1 answer:
const2013 [10]3 years ago
8 0

Answer:    The risk of obsolescence

Explanation:  This is in fact the risk that some process, technology or hardware used in the company is outdated, so there are newer, more innovative products, hardware, etc. In this way, the use of such outdated technologies and the like, creates the opportunity to reduce competitiveness in the market, which directly affects the point of each company, which is profit. So in this case too, the risk of obsolescence led to the situation that outdated technology, specifically, the use of an old compact disc, prevents a smooth business process. Not keeping up with new technologies creates this kind of risk, which consequently leads to the inability to access certain data required for the operation of the company, which affects profit.

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Write Java code that creates an array of n integers myArray, by taking n integers from the user with duplications, and do the fo
skad [1K]

Answer:

this should be what you need

Explanation:

import java.util.*;

public class ABC{

 public static void main(String[] args) {

   int n;

   //create scanner object

   Scanner sc = new Scanner(System.in);

   //ask for size of array

   System.out.print("Enter the size of array (n): ");

   //read the input

   n = sc.nextInt();

   //create an array of n length

   int [] myArray = new int[n];

   //ask user for array elements

   System.out.printf("Enter %d integers: ", n);

   //read array elements

   for(int i =0 ;i <5; i++)

     myArray[i] = sc.nextInt();

   

   //print the elements if myArray

   System.out.print("1 - The values of myArray are: [");

   for(int i =0 ; i < n; i++){

     System.out.print(myArray[i]);

     if(i < n-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate mean and sum of myArray elements

   int sum = 0;

   double mean = 0;

   for(int i = 0; i < n; i++)

     sum += myArray[i];

   

   mean = (sum*1.0)/n;

   //print the sum and mean of myArray

   System.out.printf("2 - The sum is: %d. The mean is: %.1f\n", sum, mean);

     

   //create an arraylist

   ArrayList<Integer> myArrayList = new ArrayList<Integer>();

   //copy the value of myArray to an arraylist without duplicates

   for(int i = 0; i < n; i++){

     if(!myArrayList.contains(myArray[i]))

       myArrayList.add(myArray[i]);

   }

   sum = 0; mean = 0;

   //display the values of myArrayList

   System.out.print("3 - The values of myArrayList are: [");

   for(int i =0 ; i < myArrayList.size(); i++){

     System.out.print(myArrayList.get(i));

     if(i < myArrayList.size()-1)

       System.out.print(", ");

   }

   System.out.print("]\n");

   //calculate sum and mean of myArrayList elements

   for(int i = 0; i < myArrayList.size(); i++)

     sum += myArrayList.get(i);

   mean = (sum*1.0)/myArrayList.size();

   //print the sum and mean of myArrayList

   System.out.printf("4 - The sum is: %d. The mean is: %.2f\n", sum, mean);

 }

}

3 0
3 years ago
Carly wants to be able to look at a document without having to use the horizontal scroll bar located on the bottom of the screen
Leno4ka [110]

Answer:

I think it's "Carly will set the page to Page Width, and Rhianna would zoom to 150%." If Carly doesn't want to use the zoom thingy, then she probably would just change the page orentation (idk if I spelled that right). Rhianna wants to zoom in, so that's why I said that. It's either "A" or "C."

Explanation:

I hope this helps!

5 0
3 years ago
Which one of the following is the correct code snippet for calculating the largest value in an integer array list aList?
vodka [1.7K]

Answer:

Option a.  int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }

is the correct code snippet.

Explanation:

Following is given the explanation for the code snippet to find largest value in an integer array list aList.

  1. From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
  2. By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
  3. If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
  4. When the loop will end, the variable max will have the greatest value from the array aList.

i hope it will help you!

7 0
3 years ago
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Which type of input peripheral is most prevalent in a Point of Sale system?A. External USB storage.
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Answer:

B. Card reader.

Explanation:

Peripheral devices are generally auxiliary devices such as mouse, keyboard, card reader, pen drives, microphones, graphics cards, etc. that are connected with the computer are work in some way with it. In Point of sale (POS) devices card reader are used to read debit or credit cards.

4 0
3 years ago
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Which of the following is NOT a possible duty for a professional working in the Web and Digital Communications pathway?
Harlamova29_29 [7]

Answer:

creating computer software

Explanation:

HOPE THIS HELPS!!!

8 0
3 years ago
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