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3 years ago

Angle 1 is a complement of angle 2 and measure 2 equals 5 degrees find measure angle 1

1 answer:

3 0

Angle one equals 85 because when an angle is a complement of another angle that means their degrees added together equal to 90 degrees. And so you just do 90-5=85 to get your answer.

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Describe, in your own words, the identity sin^2(x) + cos^2(x) = 1.

Crank

Look at the attached figure. We define the unit circle as a circle with center $A$ in the origin (0,0) and radius 1.

Then, we consider a point P on the circumference. We call $\alpha$ the angle between the positive half of the x axis and the radius AP.

We define

$\cos(\alpha) = \overline{AD},\quad \sin(\alpha) = \overline{AC}$

As you can see, ACD is a right triangle, and so we have

$\overline{AD}^2+\overline{AC}^2=\overline{AP}^2$

But since we know that AD is the cosine, AC is the sine, and AP is the radius (which is 1, and remains 1 when squared), we have just found out that

$\cos(\alpha)^2+\sin(\alpha)^2=1$

4 0

3 years ago

Help, please!! What is x?? x/2+3/8=1

svetlana [45]

Answer:

8(x/2) + 8(3/8) = 1(8)

8(x/2)..the two cancels out and you are left with 4x

8(3/8)..the 8 cancels and leaves with 3

1(8)=8

4x+3=8

Subtract the 3 from both sides to get the x term alone

4x=5

Divide both sides by x to get alone

x=5/4

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which are the independent events? Check all that apply

olya-2409 [2.1K]

Answer:

Independent events are those that do not depend on others. Two entities does not depend on each other. The change in one entity does not change the other.

So, independent events here are-

1. rolling a number cube twice.

2. flipping a coin 4 times.

3. choosing a meal combination.

Rest two options are dependent on each other.

4 0

4 years ago

Read 2 more answers

Simplify (2^3)^–2 ment to put this

aleksley [76]

Answer:

$\frac{1}{64}$

Step-by-step explanation:

$\left(2^3\right)^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(2^3\right)^{-2}=2^{3\left(-2\right)}\\\\3\left(-2\right)=-6\\=2^{-6}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\2^{-6}=\frac{1}{2^6}\\\\2^6=64\\\\=\frac{1}{64}$

4 0

4 years ago

Read 2 more answers

Pls help with the last two

Vanyuwa [196]

Answer:

6 to 12 to 48

Step-by-step explanation:

that's the answer sorry if it's wrong

7 0

3 years ago