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ASHA 777 [7]
3 years ago
7

6000 and 200 feet greater than less than or equal to 1 mile and 900 feet

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
6000 and 200 feet is greater than 1 mile and 900 feet
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Write an equation in slope intercept form for the cost at each store
Allushta [10]

Answer:

See attachment

Step-by-step explanation:

On attachment

7 0
3 years ago
i drink 10 liters of water on weekdays and 4 liters of water on the weekend how many liters of water i drink per day
MariettaO [177]
The answer is 40. Just multiply 10x4 and you get the answer
7 0
3 years ago
Condense (cos92°)(cos133°)-(sin92°)(sin133°) into a singular trigonometric function expression, then find the exact value.
goldenfox [79]

Answer:

-1/√2  

Step-by-step explanation:

According to trigonometry identity

cos(A+B) = cosAcosB - sinA sinB

Given the expression

(cos92°)(cos133°)-(sin92°)(sin133°)

This can be expressed as cos(92+133) where A = 92, B = 133

(cos92°)(cos133°)-(sin92°)(sin133°)

= cos(92+133)

= cos225

= -0.7071

= -1/√2

Hence the exact value is  -1/√2  

7 0
3 years ago
a blueprint has a scale of 1/8 in = 1 foot the drawing shows width of a window to be 3/4 inches wide what is the actual of the w
kobusy [5.1K]
6 Feet.

Divide the width of the window in the blueprint by the set scale, 1/8.
8 0
3 years ago
a rectangle has a width that is 7 centimeters less than its length, and it’s area is 330 square centimeters. what are the dimens
WINSTONCH [101]

Answer:

The dimensions of the rectangle are 22cm of length and 15cm of width

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of ​​a rectangle

a = area = 330 cm²

L = length  =

w = width = L - 7cm

a = l * w

we replace with the known values

330 cm² = L * (l - 7cm)

330 cm² = L² - 7Lcm

0 = L² - 7Lcm - 330 cm²

when we have an equation like this we can use bhaskara

a = 1

b = -7Lcm

c = -330cm²

ax² + bx + c = 0

x = -b(±)√(b² - 4ac)/2a

we replace with the known values

L = -(-7cm)(±)√(7² - 4(1)(-330cm²)) / 2(1)

L = 7cm(±)√(49 + 1320cm²)) / 2

L = 7cm(±)√(1369cm²)) / 2

L1 = (7cm + 37cm) / 2

L1 = 44cm / 2 = 22cm

L2 = (7cm - 37cm) / 2

L2 = -30cm / 2 = -15cm

The positive represents the unknown with which we work (L) and the negative with which we do not work (W)

The dimensions of the rectangle are 22cm of length and 15cm of width

6 0
3 years ago
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