An average person in the United States throws away 4.5 × 10² g of trash per day. In 2013, there were about 3.2×1063.2×10^6 peopl
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Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:
*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
2x-3y = 8
Add 3y on both sides
2x = 8 + 3y
Subtract 8 on both sides
3y = 2x - 8
Divide 3 on both sides
Add 3y on both sides
2x = 8 + 3y
Subtract 8 on both sides
3y = 2x - 8
Divide 3 on both sides
This sequence has generating function
(if we include for a moment)
Recall that for , we have
Take the derivative to get
Take the derivative again:
Take the derivative one more time:
so we have