If an integer m is divisible by both 10 and 12, then it must also be divisible by which of the following?
1 answer:
Answer:
20
Step-by-step explanation:
an integer m is divisible by both 10 and 12
Lets write the prime factor for each number
the prime factor for 10 is 5,2
the prime factor for 12 is 3,2,2
Now take the product of the prime factors that are not in common and also in common
60 is divisible by 20
so answer is 20
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7x + 2y = 2
2x - y = 10
2y = - 7x + 2
- y = - 2x + 10
2y = -7x + 2
y = 2x - 10
y= 2x - 10
y = -3.5x + 1
y = 2x - 10
Now, let's find "x" first by doing a substituion !
2x - 10 = - 3.5x + 1
y = 2x - 10
2x + 3.5x = 1 + 10
y = 2x - 10
5.5x = 11
y= 2x - 10
y= 2*2 - 10 = 4 - 10 = -6
In short, the answer would be : y = -6 (Option B).
Hope this helps !
Photon
2x - y = 10
2y = - 7x + 2
- y = - 2x + 10
2y = -7x + 2
y = 2x - 10
y= 2x - 10
y = -3.5x + 1
y = 2x - 10
Now, let's find "x" first by doing a substituion !
2x - 10 = - 3.5x + 1
y = 2x - 10
2x + 3.5x = 1 + 10
y = 2x - 10
5.5x = 11
y= 2x - 10
y= 2*2 - 10 = 4 - 10 = -6
In short, the answer would be : y = -6 (Option B).
Hope this helps !
Photon