First angle= x+10
Second angle = x
Third angle = x+x+10 or 2x+10
X+10+x+2x +10=180
4x+20=180
Subtract 20 from both sides
4x=160
Divide both sides by 4
X=40
First angle =50
Second angle=40
Third angle =90
Answer: −(b+4)(2b−3)
Step-by-step explanation:
1. Factor out the negative sign.
−(2b^2+5b−12)
2. Split the second term in 2b^2+5b−12 into two terms.
−(2b^2+8b−3b−12)
3.Factor out common terms in the first two terms, then in the last two terms.
−(2b(b+4)−3(b+4))
4. Factor out the common term b+4b+4b+4.
−(b+4)(2b−3)
What is the shape for your problem?
Answer:
D
Step-by-step explanation:
side HG is 3
side FG is 5 hypotenuse
sin F = 3/5 = opposite/hypotenuse
cos G is adjacent/hypotenuse
adjacent side is HG which = 3
hypotenuse is 5
Answer:
13
Step-by-step explanation:
a^2 + b^2 = c^2
11^2 + 7 ^2 = c^2
121 + 49 = 170
√170 = 13.04
