Consider the following class declarations.

The company generates a lot of revenue and is rapidly growing. They're expecting to hire hundreds of new employees in the next y

uysha [10]

Answer:

The most appropriate way to deal with the situation presented above is to acquire more space at the current office site at additional rent beforehand.

Explanation:

The Scaling of a revenue-generating business is a crucial task in which a lot of pre-planning and thinking is required.

In order to scale the business in the next year, the planning of it is to be carried out at the moment and proper necessary arrangements are ensured. These steps could be one from:

Looking for bigger spaces for renting for a full shift of the operations
Looking for a site office for an additional office
Acquiring more space in the current office site.

This process would result in acquiring a bigger place beforehand but in order to mitigate the risk, try to keep the place in view by providing them a bare minimum advance for the additional units.

8 0

2 years ago

Consider the following high-level recursive procedure: long long int flong long int n, long long int k long long int b b k+2; if

Stolb23 [73]

Answer:

f(long long, long long):

push rbp

mov rbp, rsp

push rbx

sub rsp, 40

mov QWORD PTR [rbp-40], rdi

mov QWORD PTR [rbp-48], rsi

mov rax, QWORD PTR [rbp-48]

add rax, 2

mov QWORD PTR [rbp-24], rax

cmp QWORD PTR [rbp-40], 0

jne .L2

mov QWORD PTR [rbp-24], 8

jmp .L3

.L2:

mov rax, QWORD PTR [rbp-40]

lea rdx, [0+rax*4]

mov rax, QWORD PTR [rbp-24]

lea rbx, [rdx+rax]

mov rax, QWORD PTR [rbp-48]

lea rdx, [rax+1]

mov rax, QWORD PTR [rbp-40]

sub rax, 1

mov rsi, rdx

mov rdi, rax

call f(long long, long long)

add rax, rbx

mov QWORD PTR [rbp-24], rax

.L3:

mov rdx, QWORD PTR [rbp-24]

mov rax, QWORD PTR [rbp-48]

add rax, rdx

add rsp, 40

pop rbx

pop rbp

ret

Explanation:

8 0

2 years ago

Using recursion, write a program that asks a user to enter the starting coordinates (row, then column), the ending coordinates (

Luden [163]

Answer:

The program in Python is as follows

def Paths(row,col):

if row ==0 or col==0:

return 1

return (Paths(row-1, col) + Paths(row, col-1))

row = int(input("Row: "))

col = int(input("Column: "))

print("Paths: ", Paths(row,col))

Explanation:

This defines the function

def Paths(row,col):

If row or column is 0, the function returns 1

if row ==0 or col==0:

return 1

This calls the function recursively, as long as row and col are greater than 1

return (Paths(row-1, col) + Paths(row, col-1))

The main begins here

This prompts the user for rows

row = int(input("Row: "))

This prompts the user for columns

col = int(input("Column: "))

This calls the Paths function and prints the number of paths

print("Paths: ", Paths(row,col))

4 0

2 years ago

Programming hooks, or guidelines, published by firms that tell other programs how to get a service to perform a task such as sen

RideAnS [48]

Answer:

"Application programming interface(API)" is the correct answer for the above question.

Explanation:

API is an interface which is used to call the different software in the currently developing software by the developer to inbuilt some task of that software.
The full of this is the Application programming interface. It is an interface or guidelines which are used to tell the other software, that how a particular service is performed.
The above concept is asked by the above question. so the answer is API.

4 0

3 years ago

A milk carton can hold 3.78 liters of milk. Each morning, a dairy farm ships cartons of milk to a local grocery store. The cost

makvit [3.9K]

Answer:

milk_produced = float(input("Enter the total amount of milk produced in the morning: "))

liter_cost = float(input("Enter the cost of producing one liter of milk: "))

carton_profit = float(input("Enter the profit on each carton of milk: "))

carton_needed = round(milk_produced / 3.78)

cost = milk_produced * liter_cost

profit = carton_profit * carton_needed

print("The number of milk cartons needed to hold milk is " + str(carton_needed))

print("The cost of producing milk is " + str(cost))

print("The profit for producing milk is " + str(profit))

Explanation:

*The code is in Python.

Ask the user to enter milk_produced, liter_cost and carton_profit

Calculate the number of milk cartons needed, divide the milk_produced by the capacity (3.78) of a cartoon and round the result

Calculate the cost, multiply the milk_produced by liter_cost

Calculate the profit, multiply the carton_profit by carton_needed

Print the results

3 0

2 years ago