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Fed [463]
3 years ago
11

NEED HELP!!! Use what you know about special right triangles to find the missing measures. Show all calculations that lead to yo

ur final results. Please show calculations as well.

Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Answer:a) a=22, b=11

b) m=7\frac{\sqrt{2} }{2}, n= \frac{98-7\sqrt{2} }{2}

Step-by-step explanation:

You should use trigonometry ratios as required and then you should use pythagoras theorem

In a) cosine(30°)= base/hypotenuse,

where 11√3 is the base

"a" is hypotenuse and

"b" is perpendicular

from this you can find the value of perpendicular then you should use pythagoras theorem to find the value of hypotenuse

pythagoras theorem is

base²+perpendicular²= hypotenuse²

Same is applied on (b) right triangle as, sine(45°)=perpendicular/hypotenuse

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8 0
3 years ago
Please Answer its timed The dimensions of a rectangle are represented by the functions shown. g(x)+3x-4 f(x)=2x-9 Which function
Alenkasestr [34]

Answer:

\boxed{6x^2-35x+36}

Step-by-step explanation:

The dimensions of the rectangle are represented by functions:

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The area is length × width of a rectangle.

length \times width

(3x-4)(2x-9)

Expand brackets and solve.

6x^2-27x-8x+36

6x^2-35x+36

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=solve%20%5C%3A%20%20%5C%5C%20%20%5C%5C%20find%20%5C%3A%20the%20%5C%3A%20area%20%5C%3A%20of%20%
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Area = l ×b

a  = l \times b \\ a = 11 \times 9 \\ a = 99

5 0
3 years ago
There are two numbers. The first number minus the second number is 15. One-third of the sum of the numbers is one quarter of the
disa [49]

Answer:

So the numbers are 12 and -3.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:

x - y = 15

Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:

(1/3)*(x+y) = x/4

Since we now have two equations and two variables we can solve for x and y. From the first equation we have:

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Using this expression for the value of y in the second equation:

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(1/3)*(2*x - 15) = x/4

2*x - 15 = 3*x/4

2*x - 3*x/4 = 15

(8*x - 3*x)/4 = 15

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5*x = 60

x = 60/5 = 12

y = x - 15 = 12 - 15 = -3

So the numbers are 12 and -3.

4 0
2 years ago
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What is the volume of a sphere with a radius of 3 inches
posledela
The\ volume\ of\ a\ sphere:V=\dfrac{4}{3}\pi R^3\\\\R=3\ in\\\\V=\dfrac{4}{3}\pi\cdot3^3=\dfrac{4}{3}\pi\cdot27=4\pi\cdot9=36\pi\\\\Answer:\boxed{V=36\pi\ in^3}
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3 years ago
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