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Fed [463]
3 years ago
11

NEED HELP!!! Use what you know about special right triangles to find the missing measures. Show all calculations that lead to yo

ur final results. Please show calculations as well.

Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Answer:a) a=22, b=11

b) m=7\frac{\sqrt{2} }{2}, n= \frac{98-7\sqrt{2} }{2}

Step-by-step explanation:

You should use trigonometry ratios as required and then you should use pythagoras theorem

In a) cosine(30°)= base/hypotenuse,

where 11√3 is the base

"a" is hypotenuse and

"b" is perpendicular

from this you can find the value of perpendicular then you should use pythagoras theorem to find the value of hypotenuse

pythagoras theorem is

base²+perpendicular²= hypotenuse²

Same is applied on (b) right triangle as, sine(45°)=perpendicular/hypotenuse

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What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)
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so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).

\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}

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\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill

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3 years ago
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