I’m not sure if your asking help to factor the equation. Here is the answer to the equation that I factored. -v^3(v^72-2v^24 + 1) Hope that helps you.
Problem 1, part (a)
<h3>Answer: False</h3>
For instance, 200 feet in real life can be reduced to scale down to say 2 inches on paper. So we have a reduction going on, and not an enlargement.
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Problem 1, part (b)
<h3>Answer: true</h3>
This is because a scale drawing involves similar polygons. This is true whenever any dilation is applied.
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Problem 2
I'm not sure how your teacher wanted you to answer this question. S/he didn't give you any numbers for the side lengths of the polygon. The angle measures are missing as well.
Answer:
11.64
Step-by-step explanation:
100%-> 48
15%-> 7.20
6.25%-> 3
48+7.20+3=58.20
58.20÷5=11.64
You do 9+3 which equals 12 then you multiply that by 4
Answer:
The sample size required is, <em>n</em> = 502.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:
The margin of error is:
Assume that 50% of the people would support this political candidate.
The margin of error is, MOE = 0.05.
The critical value of <em>z</em> for 97.5% confidence level is:
<em>z</em> = 2.24
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2.24%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%7D%7B0.05%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D501.76%5C%5C%5C%5C%5Capprox%20502)
Thus, the sample size required is, <em>n</em> = 502.
