Hey there,
First, find the square root of the given equation.
Keep in mind that this is solved for k = 0 and 1.
Second, simplify.
Best of Luck!
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
I will send hint follow this hint then slove it .
thankyou
Side GF^2 = 144 -100
Side GF^2 = 44
Side GF = 2*sqrt(11)
Side GF = 6.6332
Perimeter = 6.6 + 10 + 12
Perimeter = 28.6
Answer is 29 units
Answer:
hi its simple.
Step-by-step explanation:
9;3
or simplified...
3;1
Answer:
A square has 4 sides of equal length, so if you have been given the length, this is also the breadth.
Therefore, the perimeter is 4 x side length.
For example, imagine a square with side length 3 cm. As all four side lengths are equal, the perimeter would be 4 x 3 cm = 12 cm
