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konstantin123 [22]
4 years ago
7

A group of friends will be buying at most 10 items at the concession stand at the high school football game. They have no more t

han $25 to spend at the game. Each hot food item is #3 and each cold food item is $2. The system of inequality graphed below represents this information. Which combination of hot and cold food items could the group buy? 0 hot items and 11 cold items, 9 hot items and 1 cold item, 2 hot items and 8 cold items, 6 hot items and 4 cold items
Mathematics
2 answers:
Andru [333]4 years ago
7 0

Answer:

0 hot items and 11 cold Items

Step-by-step explanation:

The other combinations will be more than $25 but

11(3)=22 which is even lower than $25

Eva8 [605]4 years ago
4 0

<em><u>Answer:</u></em>

0 hot items and 11 cold items

<em><u>Step-by-step explanation:</u></em>

He has 25 dollars to spend.

Hot: 3

Cold: 2

<em>Let's eliminate some wrong answers.  </em>

1. <u>0 hot items and 11 cold items:</u> Possible, because 11 times 2 is 22.

2. <u>9 hot items and 1 cold item: </u>Impossible, because 9 times 3 = 27 and that is already over 25 dollars. This one is eliminated.

3. <u>2 hot items and 8 cold items:</u> 2 times 3 is 6. 8 times 2 is 16. 16 + 3 = 19. He buys 10 items here. Selection one bought 11 items though, so this one is eliminated.

4. <u>6 hot items and 4 cold items:</u> 6 times 3 is 18, and 4 times 2 is 8. 18 + 8 = 26. He doesn't have enough money, so this one is eliminated.

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