What is the answers help me asap

Help please? thank you

Alexxandr [17]

9514 1404 393

Answer:

RS = √(b² +(c -a)²)

Step-by-step explanation:

Put the given point coordinates in the given formula:

R = (x₁, y₁) = (0, a)
S = (x₂, y₂) = (b, c)

RS = √((b -0)² +(c -a)²)

RS = √(b² +(c -a)²)

8 0

2 years ago

The ratio of 3 km to 1800 m is

Ugo [173]

5 : 3

D1 = 3km = 3000 m (1km = 1000m)
D2 = 1800m

Ratio of D1:D2
=3000/1800
=1000/600 (dividing by 3)
=10/6 (dividing by 100)
=5/3 (dividing by 2)

= 5 : 3

6 0

2 years ago

Use the distributive property to remove the parentheses.

kifflom [539]

Answer:

10x + 8y - 2

Step-by-step explanation:

$-2(-5x – 4y+1) \\ \\ = ( - 2)( - 5x) - 2 ( - 4y) - 2 \times 1 \\ \\ = 10x + 8y - 2$

3 0

3 years ago

Prove that sin²∅+cos²∅=1 ?

sasho [114]

Step-by-step explanation:

Let ABC be a right angled triangle where there's a right angle in B . Let the measure of the angle BAC be ∅. So,

$\sin(∅) = \frac{BC}{AC}$

$= > {\sin}^{2}∅ = \frac{ {BC}^{2} }{ {AC}^{2} }$

Also,

$\cos(∅) = \frac{AB}{AC}$

$= > { \cos}^{2}∅ = \frac{ {AB}^{2} }{ {AC}^{2} }$

Now adding the values of sin^2∅& cos^2∅,

${ \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {BC}^{2} }{ {AC}^{2} } + \frac{ {AB}^{2} }{ {AC}^{2} }$

$= > { \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {AB}^{2} + {BC}^{2} }{ {AC}^{2} }$

But we know that

${AC}^{2} = {AB}^{2} + {BC}^{2}$ by applying Pythagorean Theorem

So ,

$= > { \sin}^{2} ∅ + { \cos}^{2} ∅ = \frac{ {AC}^{2} }{ {AC}^{2} } = 1$

7 0

2 years ago

A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

2 years ago