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3 years ago

10

IM USING UP SO MANY POINTS CAUSE PEOPLE WONT ANSWER PLZ HELP-A business owes $8000 on a loan. Every month, the business pays 12

of the amount remaining on the loan.
How much will the business pay in the sixth month?

1 answer:

allsm [11]3 years ago

8 0

He pays $125 during the sixth month.

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Which polynomials are prime? Check all that apply.

insens350 [35]

15x2+10x-9x+7
8x3+20x2+3x+12
11x4+4x2-6x2-16
Hope this helps !!

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3 years ago

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Solve c =(a² + 3b)/4 for b.<br><br>Bruv take all my points I literally blow at math :'(

Sati [7]

Answer:

$b=\frac{4c-a^{2} }{3}$

Step-by-step explanation:

First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division

Then, you have $4c=a^{2} +3b$

Subtract both sides by a squared

DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition

From that you get $4c-a^{2} =3b$

Finally, divide both sides by 3.

You get $b=\frac{4c-a^{2} }{3}$

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3 years ago

Solve the equation, 4 - (x + 1) = 6.<br><br> x = -3<br> x = 3<br> x = -9<br> x = 9

Vinvika [58]

Answer:

Step-by-step explanation:

The negative in front of the parenthesis changes the signs of the numbers and variables inside the parenthesis. We can rewrite as

4 - x - 1 = 6 and

3 - x = 6 so

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3 years ago

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zheka24 [161]

Step-by-step explanation:

${x}^{65559$

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3 years ago

Use a double angle or half angle identity to find the exact value of each expression

inna [77]

<em>θ</em> is given to be in the fourth quadrant (270° < <em>θ</em> < 360°) for which sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. This means

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1 ==> sin(<em>θ</em>) = -√[1 - cos²(<em>θ</em>)] = -3/5

Now recall the double angle identity for sine:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

==> sin(2<em>θ</em>) = 2 (-3/5) (4/5) = -24/25

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3 years ago