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lys-0071 [83]
2 years ago
10

IM USING UP SO MANY POINTS CAUSE PEOPLE WONT ANSWER PLZ HELP-A business owes $8000 on a loan. Every month, the business pays 12

of the amount remaining on the loan.
How much will the business pay in the sixth month?
Mathematics
1 answer:
allsm [11]2 years ago
8 0
He pays $125 during the sixth month.
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What is the value of f(g(3))
denpristay [2]

Answer:

A

Step-by-step explanation:

f(g(3)= f(g(x=3)) = f(\frac{3+1}{3-1}) = f(4/2) = f(2) = f(x=2) = 3*2-7 = 6-7 = -1

7 0
2 years ago
Read 2 more answers
4 16/17 as a improper fraction
Allushta [10]

Answer:

\frac{84}{17}

Step-by-step explanation:

  1. Formula for mixed number to improper fraction: (Whole number × denominator) + numerator
  2. 4 × 17 = 68, 68 + 16 = 84
  3. Re-write the fraction: \frac{84}{17}  

I hope this helps!

7 0
3 years ago
Read 2 more answers
Round 71290 to the nearest 10 what's the answer?
Aloiza [94]
71290 because the ones are 0 and zero is lower than 5 
so it wouldn't add anything to the tens 

the rule is if the number is more than 5+ it will add 1 to the next number
for example if we have this number 189 and we want to round it to the nearest 10 ..
we will see the ones place is it more than 5+ ? YEAH bcz its 9 ...
so 9 will add one to the tense and the answer will be 190 :) 

hope you got the point .
6 0
3 years ago
the constant of proportionality is always the point_______, where k is the constant of proportionality. Additionally, you can fi
MArishka [77]

Answer:

Step-by-step explanation:

When two variables say x and y are proportional let us assume y dependent variable and x independent variable

then we have y =kx

Here k is called the constant of proportionality.

Whenever x increases/decreases by 1 unit, the y value also increases/decreases by k units.

Whenever x=1, y =k

and always \frac{y}{x} =k

Thus we can fill up as

the constant of proportionality is always the point___(1.k)____, where k is the constant of proportionality. Additionally, you can find the constant of proportionality by finding the ratio of___y to x____, for any point on the___graph of the function.___.

5 0
2 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
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