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Alexxx [7]
3 years ago
15

Fatima evaluated the expression StartFraction 4 m Superscript negative 3 Baseline n Superscript negative 2 Baseline Over m Super

script negative 1 Baseline n EndFraction, when m = negative 2 and n = 4. Her work is shown below. StartFraction 4 m Superscript negative 3 Baseline n Superscript negative 2 Baseline Over m Superscript negative 1 Baseline n EndFraction = 4 m Superscript negative 2 Baseline n Superscript negative 3 Baseline = 4 (negative 2) Superscript negative 2 Baseline (4) Superscript negative 3 Baseline = StartFraction 1 Over 64 EndFraction times StartFraction 1 Over 64 EndFraction = StartFraction 1 Over 4,096 EndFraction What was Fatima’s error?
Mathematics
2 answers:
makkiz [27]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Marysya12 [62]3 years ago
7 0

Answer:

She applied the exponent Negative 2 to 4 (negative 2) instead of applying the exponent to just Negative 2.

Step-by-step explanation:

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Charlie tosses five coins.What is the probability that all five coins will land tails up.
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What is a1? what is d? what’s the equation? what is a7? what is a59?
Zina [86]
Answer:

a1 = 2

d = 3

an = 2 + (n - 1) * 3

a7 = 20

a59 = 176

Steps:

a1 is the initial value (when n equals 1), and since there are 2 crosses, it is 2.

d is the added value to each amount of crosses. And since the second amount is 5 and the third amount is 8, we can determine that each n is adding 3 crosses, therefore making d = 3.

The equation is simply plugging in the values for a1 and d.

A7 is simply plugging in 7 for n in the equation and solving for it. So;

a7 = 2 + (7 - 1) * 3

a7 = 2 + 6 * 3

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And same thing as the last for 59 except substitute 59 in for where you put 7;

a59 = 2 + (59 - 1) * 3

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8 0
3 years ago
Read 2 more answers
How do I start This?
pav-90 [236]
\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{unit}{cost}&\stackrel{total}{value}\\
&------&------&------\\
Raisins&11&2.30&25.3\\
Peanuts&p&4.50&4.5p\\
------&------&------&------\\
mixture&m&3.29&3.29m
\end{array}

we know that, the mixture amount is the sum of 11 + p, or 11 + p = m.

we also know that, the total value is also a sum of 25.3 + 4.5p = 3.29m.

\bf \begin{cases}
11+p=\boxed{m}\\
25.3+4.5p=3.29m\\
----------\\
25.3+4.5p=3.29\left( \boxed{11+p} \right)
\end{cases}
\\\\\\
25.3+4.5p=36.19+3.29p\implies 1.21p=10.89\implies p=\cfrac{10.89}{1.21}
\\\\\\
p=\stackrel{lbs}{9}
5 0
3 years ago
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