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Lelu [443]
3 years ago
10

Vanessa draws one side of equilateral

Mathematics
1 answer:
irinina [24]3 years ago
8 0

Answer:

According to my calculation, the two possible coordinates of vertex C, is (1,\sqrt{27}) and (1,-\sqrt{27}).

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Help me with this please
Reika [66]

Answer:

$2,459.21

Step-by-step explanation:

(see attached for reference)

recall that the formula for compound interest is:

A = P [ 1 + (r/n)^ (nt) ]

where,

A = Final amount ( we are asked to find this)

P = principal amount = given as $2,340

r = Annual Interest Rate = given as 5% = 0.05

n = number of times compounded in a year = 4 (compounded quarterly)

t= time = 1 year

Substituting the values into the equation,

A = P [ 1 + (r/n)^ (nt) ]

A = 2,340 [ 1 + (0.05/4)^ (4·1) ]

A = $2,459.21

6 0
3 years ago
Plzzz helpppppp nowwwww
snow_lady [41]

Answer:

x= 10

I hope i helped, best of luck!

4 0
3 years ago
Read 2 more answers
Use the permutation formula to solve a problem when n = 15 and r = 4.
barxatty [35]

nPr =  \frac{n!}{(n - r)!}

15P4 =  \frac{15!}{(15 - 4)!} = \frac{15!}{11!} \\  = \frac{15 \times 14 \times 13 \times 12 \times 11!}{11!} \\ 15 \times 14 \times 13 \times 12 = 32760

3 0
3 years ago
Read 2 more answers
what equation is used to represent "three minus the difference of a number and one equals one-half of the difference of three ti
sesenic [268]
(n-1)-3=1/2(3n-4)
hope it hrlps
8 0
4 years ago
PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.
Step2247 [10]

After using the property of power, the expressions as a power of the number a is (a^3)^{-2} = a^{-6} , (a^{-1}\cdot a^{-2})^{-3} = a^{9} and ((a^2)^{-2})^2=a^{-8} .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is (a^3)^{-2}.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

Simplifying the expression.

(a^3)^{-2} = a^{3*(-2)}

(a^3)^{-2} = a^{-6}

The second expression is (a^{-1}\cdot a^{-2})^{-3}

Using the property of multiplication of power; (a^m)^n=a^{mn}.

(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}

(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}

Using the property of sum of power a^m\cdot a^n=a^{m+n}

(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}

(a^{-1}\cdot a^{-2})^{-3} = a^{9}

The third expression is ((a^2)^{-2})^2.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=((a^2)^{(-2)\times2})

((a^2)^{-2})^2=(a^2)^{-4}

Again using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=a^{2\times(-4)}

((a^2)^{-2})^2=a^{-8}

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0
1 year ago
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