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AlladinOne [14]
3 years ago
10

A light bulb consumes 6480 watt-hours in 4 days and 12 hours. How many watt-hours does it consume per day?

Mathematics
2 answers:
Orlov [11]3 years ago
8 0
<span>
x=1440*4.75
x=6840
That is how you answer it I'm pretty sure </span>
goldfiish [28.3K]3 years ago
8 0
Convert 4 days to hours=24*4+12
then you divde 6480 by it
6480/108= 60

pls mark as brainliest
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(c + a = 800)5
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3 0
3 years ago
Solve for x and y 10x + 7y = 1435
bearhunter [10]
Move all terms that don't contain x to the right side and solve.
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6 0
3 years ago
Read 2 more answers
Apel Sinoman has 100 ft of fencing material to enclose a rectangular exercise run for her dog. One side of the run will border h
Olegator [25]

Answer:

For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

Step-by-step explanation:

Let the length of the rectangular exercise run = l ft

and width of the run = w ft

Sinoman has to cover a rectangular exercise run from three sides with the fencing material,

So length of the material = (l + 2w) ft

l + 2w = 100

l = 100 - 2w --------(1)

Area of the rectangular area covered = Length × width

A = lw

A = w(100 - 2w)    [(l = 100 - 2w)from equation (1)

For maximum area we find the derivative of area and equate it to zero.

\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]

A'=\frac{d}{dw}(100w-2w^{2} )

A' = 100 - 4w

For A' = 0

100 - 4w = 0

4w = 100

w = 25 ft

From equation (1)

l = 100 - 2w

l = 100 - 2×(25)

l = 50 ft

Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

5 0
3 years ago
What is the point-slope form of a line that has a slope of 5 and passes through point (-7, 2)?
Katarina [22]

Answer:

y - 2 = 5(x + 7)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 5 and (a, b) = (- 7, 2), hence

y - 2 = 5(x - (- 7)), that is

y - 2 = 5(x + 7)

5 0
3 years ago
Read 2 more answers
The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let μ denote the true average re
tatuchka [14]

Answer:

We conclude that average reflectometer reading for a new type of paint is greater than 20

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 20

Sample size, n = 13

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 20\\H_A: \mu > 20

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} } = 3.2

Degree of freedom = n - 1 = 13 - 1 = 12

Now, we calculate the p-value with the help of standard table.

P-value = 0.004

Since, the p-value is less than the significance level, we fail to accept the null hypothesis and reject it.

Thus, there is enough evidence to support that average reflectometer reading for a new type of paint is greater than 20

5 0
3 years ago
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