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balu736 [363]
4 years ago
12

Solve x2 + 6x + 7 = 0. (2 points)

Mathematics
2 answers:
Effectus [21]4 years ago
8 0

Answer:

x=-3+\sqrt{2}\text{ and }x=-3-\sqrt{2}

Step-by-step explanation:

Given quadratic equation,

x^2 + 6x + 7 = 0

By quadratic formula,

x=\frac{-6\pm \sqrt{6^2-4\times 1\times 7}}{2\times }

=\frac{-6\pm \sqrt{36-28}}{2}

=\frac{-6\pm \sqrt{8}}{2}

=\frac{-6\pm 2\sqrt{2}}{2}

=-3\pm \sqrt{2}

\implies x=-3+\sqrt{2}\text{ or }x=-3-\sqrt{2}

Hence, the solution of the given equation are,

x=-3+\sqrt{2}\text{ and }x=-3-\sqrt{2}

Art [367]4 years ago
7 0

Answer:

x=-3-\sqrt{2} or x=-3+\sqrt{2}

Step-by-step explanation:

The given equation is

x^2+6x+7=0

Comparing to ax^2+bx+c=0, we have a=1,b=6,d=7

The solution to this equation can be obtained using the quadratic formula;

x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

Plug in the values to get;

x=\frac{-6\pm \sqrt{6^2-4(1)(7)} }{2(1)}

x=\frac{-6\pm \sqrt{36-28} }{2}

x=\frac{-6\pm \sqrt{8} }{2}

x=\frac{-6\pm 2\sqrt{2} }{2}

x=-3-\sqrt{2} or x=-3+\sqrt{2}

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