The average speed, in km/minute, of the train is 2.79 km/minute
<h3>Calculating average speed </h3>
From the question, we are to calculate the average speed in km/minute
From the given information,
Distance travelled = 503 km
Time taken = 3 hours = 3 × 60 minutes = 180 minutes
Using the average speed formula,
Average speed = Distance / Time
∴ Average speed of the train = 503 / 180
Average speed of the train = 2.79 km/minute
Hence, the average speed, in km/minute, of the train is 2.79 km/minute
Learn more on Calculating average speed here: brainly.com/question/12025128
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FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE. For this case what we have is the following:
For the two semicircles we can model it as a complete circle.
We have to then:
Perimeter:
P = 2 * pi * r
or
P = pi * d
Where,
r = radius
d = diameter
Therefore the perimeter is:
P = 10 * pi
For the largest circle we have:
radius = 10
Perimeter:
P '= 2pi10
P '= 20pi
1/4 since 1/4 circle:
P '' = 20pi / 4 = 5pi
Then, the total perimeter of the source is:
Pt = P + P '' = 10pi + 5pi = 15pi
Pt = 15 * (3.141592)
Pt = 47.1239
round
Pt = 47.1 ft
Area:
The total area will be:
A = A (two semicircles) + A (quarter big circle)
A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
A = 98.17477042 feet ^ 2
Round:
A = 98.2 feet ^ 2
Answer:
Perimeter of the source:
Pt = 47.1 ft
Area of the source:
A = 98.2 feet ^ 2
Answer: x=y-3 or y=3+x
Step-by-step explanation:
Answer:
A(10) = $13,961.50
Step-by-step explanation:
First, convert R as a percent to r as a decimal
r = R/100
r = 5.25/100
r = 0.0525 rate per year,
Then solve the equation for A
The formula is given as:
A = Pe^rt
P = 8259
r = 0.0525
t = 10 years.
Hence,
A = 8,259.00 × e^(0.0525×10)
A = $13,961.50
Therefore, the money that will be in the account after 10 years is $13,961.50
Answer:
-53
Step-by-step explanation:
If x=3 and y=-4
Plug the numbers into the equation
3 - (-4) - 3 + (-57)
Now solve the equation right to left
3 - (-4) = 7
7 - 3 = 4
4 - 57 = -53
So the answer is -53