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Novay_Z [31]
3 years ago
12

Suppose that you are running a concession stand when a person gives you $18 and asks for six drinks and as many hot dogs as the

remaining money will buy. If drinks are $1.00 and hot dogs are $1.75, what is the maximum number of hot dogs the person can buy? Write an inequality that represents your solution. Show your work.
Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

The maximum number of hot dogs that you can buy will be 6.

Step-by-step explanation:

Suppose that you are running a concession stand when a person gives you $18 and asks for six drinks and as many hot dogs as the remaining money will buy.

The drinks cost $1.00 so total cost for drinks will be = $6.

Remaining amount = 18-6=12 dollars

The cost of hot dogs are $1.75 per piece.

Let you buy x hot dogs.

We can make the following equation now;

1.75x=12

So, x = 6.8

Hence, the maximum number of hot dogs that you can buy will be 6 and you get a change of $1.50.

slega [8]3 years ago
3 0

Answer: 6 hotdogs

Step-by-step explanation:

h= hot dogs

18= 6 + h

-6   -6

6= h

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Answer:

The height of the pan is 2 inches.

Step-by-step explanation:

Given : Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12 inches and it's with is 10\frac{1}{2} inches.

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Solution :

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