Help me simplify the following expression, show steps please

The median boiling temperature of the tap water is 100°C.The median boiling temperature of the salt water is 102°C. Which statem

KiRa [710]

Answer:

The mean of the tap water boiling point is about 2 degrees Celsius less than the mean of the salt water temperature.

Step-by-step explanation:

Boiling point is the temperature at which a liquid boils or changes from liquid form to gaseous form. Water has a boiling point of 100 degrees Celsius.

Boiling point of water depends on atmospheric pressure which changes according to the height above sea level of a place.

Boiling point can also change depending on the purity of water.Water that has impurities such as salt will have a slightly higher boiling temperature.

The mean of the tap water boiling point is about 2 degrees Celsius less than the mean of the salt water temperature.

4 0

3 years ago

Which of the points listed is the same distance from the y-axis as the point (−1.5, 6)?

Volgvan

The complete question in the attached figure

we know that
<span>the distance from a point to line (y-axis) is the perpendicular line against y-axis, which is the absolute value of x-coordinates
</span>
in this problem
the point <span>(−1.5, 6)
the </span>absolute value of x-coordinates is 1.5
hence
the distance is 1.5

therefore

the answer is
the option B) the point (1.5,-3)

7 0

3 years ago

Solve 4x-2y=6 for x in terms for y

Elina [12.6K]

Answer:

x = 3 + y

Step-by-step explanation:

4x - 2y = 6

~Add 2y to both sides

2x = 6 + 2y

~Divide 2 to everything

x = 3 + y

Best of Luck!

5 0

3 years ago

PLEASE HELP ME OUT IM FAILING MATH‍♂️ Thx

OleMash [197]

Answer: -1 < x < 1

Step-by-step explanation: Solve for x.

Graph line is down below!

Hope this helps you out! ☺

-Leif-

3 0

3 years ago

what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil

dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h ∪ m ∪ C)' = 90

53 + n(h ∪ m ∪ C)' = 90

n(h ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0

3 years ago