That will depend, you have to ask yourself first how many kilobytes one picture is. Let's just say that the size of one picture is 100 kb (which is the average size of a picture) Then first you multiply 100 kb with the number of pictures which is 43. Now you have a total used up memory of 4300 kb. After that, you minus the used up memory which is 4300 kb, to the total available space which is 32,834.5 and you will get an available space of 28534.5 kb. After that, you divide the remaining available space with the size of each picture. So this will be 28534.5 divided by 100. You will get 285. You can still take 285 pictures.
(10n-5)/(5)= 2n-1
just divide
10/5 = 2 and -5/5 =-1
and you get the answer
2n-1= 2n-1
It seems confusing, but it's just breaking down the steps for you. It's done the same as any other word problem.
a. The unknown is how many minutes she used beyond the plan. So, we'll use "m" for the variable, to represent minutes.
b. 73.40 = 65 + 0.10m
The 73.40 is the total, which is why it's by itself. 65 represents the price per month for the plan, and 0.10m is the price per extra minute multiplied by the unknown amount of minutes used.
c. 73.40 = 65 + 0.10m
8.40 = 0.10m
84 = m
d. The number of minutes that Allegra went over the time that the plan allows is found by solving the equation we just wrote and solved. $0.10 is paid for every minute past the plan's allowance, meaning that "m" in the equation, when solved, shows us exactly how many minutes over Allegra went.
Given at you have an equilateral triangle, all sides have the same length.
Therefore,
First side 2x-7 = Second side x+y-9 = Third side y+5
Let us look at the second and third sides for now:
x+y-9 = y+5
x = y+5 - (y-9)
x = y-y+5+9
x = 14
Then we look at equating the first and third sides:
2x-7 = y+5
y = 2x-7-5
Substitute x =14 in the equation above:
y = 2(14)-7-5
= 28-7-5
= 21-5
= 16
The length of the third side is:
y+5 = 16 +5 = 21
Given that the length of each sides are the same in an equilateral triangle, all sides have the length 21cm.
