-3x - 3/4 = 9 helpppppppp

1 answer:

6 0

-3x - 3/4 = 9
-3x - 3/4 + 3/4 = 9 + 3/4
-3x = 9 3/4
I change 9 3/4 to improper fraction
-3x = 39/4
-3x / -3 = 39/4 / -3
X = 39/4 x -1/3 (change division to multiplication so that you can complete the problem)
X = -39/12
You can convert that if you want to -3 3/12
So x = -3 3/12
Simplify to x = -3 1/4

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Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

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Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - α)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of t for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$