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kakasveta [241]
3 years ago
13

What is the sale price of a phone that was originally $199 but that has been marked down by 15 percent? $159.15 $159.20 $169.10

$169.15
Mathematics
1 answer:
dsp733 years ago
5 0

Answer:

169.15 is the correct answer

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The temperature of a cup of coffee varies according to Newton's Law of Cooling: dT dt equals negative k times the quantity T min
Maslowich

Answer:

67.3°C

Step-by-step explanation:

A = 25, T(0) = 100, T(1) = 90, find T(4)

dT/dt = -k(T - A)

d(T - A)/dt = -k(T - A)

d(T - A)/(T - A) = -k dt

ln(T - A) = lnC - kt

T(t) -A=Ce^{-kt}\\T(t) = A + Ce^{-kt} = 25 + Ce^{-kt}\\T(0) = 25 + C = 100\\C=75

T(t) = 25 + 75e^{-kt}\\T(1) = 25 + 75e^{-k} = 90\\75e^{-k} = 65\\e^{-k} = \frac{65}{75}, k = ln\frac{75}{65} = 0.1431\\T(t) = 25+75e^{-0.1431t}\\T(4) = 25+75e^{-0.1431\times4} = 67.3

4 0
3 years ago
Jordan needs 5 pounds of chips for a party. The bags he is buying are 24 oz each. According to the number line, how many bags wi
strojnjashka [21]

Answer:

3.33 but he cant buy 3 and 1/3 of a bag of chips so 4

Step-by-step explanation:

4 0
3 years ago
Given that (-3, 5) is on the graph of f(x), find the corresponding point for the function f(x) − 4.
hram777 [196]
The graph of f(x) translates down 4 units to give f(x) - 4
So the x coordinate stays the same but the y coordinate is 4 units less

So the corresponding point is (-3, 1)
7 0
3 years ago
Lana has $15 for dinner her meal is $13.90 she wants to leave a 18% tip does she have enough explain your answer
denis-greek [22]

Start off by finding 18% of 13.90.

18%=18/100=0.18

0.18(13.9)=2.5

An 18% tip would be $2.50.


Now, to find out if Lana has enough money, add $2.50 to $13.90 to find out the total amount she would leave.  You get $16.40.  Since $16.40>$15, the answer is no because the total cost including the 18% tip is greater than $15.

3 0
3 years ago
-4 + 4d + 17 = 33<br> D = ?
cricket20 [7]

Answer:

3?

Step-by-step explanation:

I think it is 3, because...

33 - 17 = 16

16 - 4 = 12

12/4 = 3

???

7 0
3 years ago
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