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denpristay [2]
3 years ago
5

One number is half another number. The sum of the two numbers is 57. Find the two numbers

Mathematics
1 answer:
nalin [4]3 years ago
3 0

Let's call one number x and one number y.

x/2=y

x+y=57

We can set these equations equal to each other to solve for the numbers by subtracting x from both sides of the second equation. Now the equations are:

y=-x+57 and x/2=y

Since both equations equal y, they are also equal to each other:

-x+57=x/2

First, multiply both sides by 2:

-2x+114=x

Add 2x to both sides.

114=3x

Divide both sides by 3.

38=x

One of the numbers is 38. Now, we can plug 38 in for x in either of the equations to solve for y:

(38)+y=57

Subtract 38 from both sides:

y=19

The two numbers are 38 and 19.

I hope this helps :)

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My brother is in 6th grade and needs help with his math. I tried to help but I can't find any answers on it.
In-s [12.5K]

Answer:

Question 1) 17.4

Question 2) 1.7

Question 3) 2.8

Question 4) 8.6

Step-by-step explanation:

Mean absolute deviation is the average distance between the data points from the set to the mean point of the data set. It shows the variability in data or how much the data points are spread.

method to calculate Mean absolute deviation:

a. calculate mean

b. calculate absolute deviation of each data point

c. add all the deviations

d. divide absolute deviation by number of points

mean absolute deviation = ∑lx_{i}-xl / n

The given problem has four sub-parts

Solution 1:

Mean= (78+99+90+80+55+56+102+88+60+42)/10

            =  750/10

            =  75

Mean absolute deviation= ( I 78-75 I + I 99-75 I+I 90-75 I + I 80-75 I +

                                             I 55-75 I + I 56-75 I + I 102-75 I + I 88- 75 I +

                                             I 60-75 I + I 42-75 I) /10

         =  (174)/10

        =  17.4

Solution 2:

Mean = (10+13+7+12+9+8+12+10+11+13)/10

              =  (105)/10

              = 10.5

Mean absolute deviation = ( I 10-10.5 I + I 13-10.5 I + I 7-10.5 I + I 12-10.5 I +

                                              I 9-10.5 I + I 8-10.5 I + I 12-10.5 I + I 10-10.5 I +

                                               I 11-10.5 I + I 3-10.5 I) /10

       =   17/10

       = 1.7

Solution 3:

Mean= (1+7+10+5+3+3+6+12+9+4)/10

            =  60/10

            =  6

Mean absolute deviation  = ( I 1-6 I + I 7-6 I + I 10-6 I + I 5-6 I + I 3-6 I +

                                               I 3-6 I + I 6-6 I + I 12- 6 I + I 9-6 I + I 4-6 I) /10

         = (28)/10

        =  2.8

Solution 4:

Mean= (30+46+25+45+18+25+15+32+40+24)/10

            =  300/10

            =  30

Mean absolute deviation  = ( I 30-30 I + I 46-30 I + I 25-30 I + I 45-30 I +

                                               I 18-30 I + I 25-30 I + I 15-30 I + I 32-30 I +

                                               I 40-30 I + I 24-30 I) /10

         = (86)/10

        =  8.6

!

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