3 years ago

Find q, r in \mathbb{Z} so that 105 = 11q + r

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

$q=9\,,\,r=6$

Step-by-step explanation:

Division Algorithm :

As per division algorithm , for numbers a and b , there exist numbers q and r such that $a=bq+r\,\,,0\leq r< b$

Here ,

a = Dividend

b = Divisor

q = quotient

r = remainder

Given : 105 = 11q + r such that $0 \leq r < 11$

Here, clearly a = 105 , b = 11

To find : q and r

Solution : On dividing 105 by 11 , we get $105=11\times 9+6$

On comparing $105=11\times 9+6$ with $a=bq+r\,\,,0\leq r< b$ , we get $q=9\,,\,r=6$

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