Ask question

Ask question

All categories

2 years ago

12

1.25, 1.5, 1, 1.25, 2, 0.75, 2.5, 1.75, 2.5, 1 What is the mean?

1 answer:

Vlad [161]2 years ago

8 0

The answer to your question is,

1.55, take all the numbers and add them, then divide it by how many numbers there are.

-Mabel <3

You might be interested in

Help me with (d)(ii).<br><br> Thank you!

lord [1]

$q=\frac{h^{2}-k^{2}}{3m}$
Cross-multiplying and rearranging, we get:
$k^{2}=h^{2}-3mq$
or written without using latex:
k^2 = h^2 - 3mq
Can you finish now?

4 0

2 years ago

Andrew borrows $79,500 for 5 months on 6.30% interest rate in his saving account. calculate the simple interest

alukav5142 [94]

Equation i= p time r time T 79500 time .0630 time .42 Equal 21,035.7 simple interest Dos Doctor pepper on the interest, going back two time on the left which would become .0630 5 divide month of 12 which is .41666 Round to the nearest tenth which is .42

6 0

3 years ago

Find the integral <br> ∫√(9+x)/(9-x)

densk [106]

I suppose you mean

$\displaystyle \int \frac{\sqrt{9+x}}{9-x} \, dx$

Substitute y = √(9 + x). Solving for x gives x = y² - 9, so that 9 - x = 18 - y², and we have differential dx = 2y dy. Replacing everything in the integral gives

$\displaystyle \int \frac{2y^2}{18 - y^2} \, dy$

Simplify the integrand by dividing:

$\dfrac{2y^2}{18 - y^2} = -2 + \dfrac{36}{18 - y^2}$

$\implies \displaystyle \int \left(\frac{36}{18-y^2} - 2\right) \, dy$

For the first term of this new integral, we have the partial fraction expansion

$\dfrac1{18 - y^2} = \dfrac1{\sqrt{72}} \left(\dfrac1{\sqrt{18}-y} + \dfrac1{\sqrt{18}+y}\right)$

$\implies \displaystyle \frac{36}{\sqrt{72}} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

The rest is trivial:

$\displaystyle \sqrt{18} \int \left(\frac1{\sqrt{18}-y} + \frac1{\sqrt{18}+y}\right) \, dy - 2 \int dy$

$= \displaystyle \sqrt{18} \left(\ln\left|\sqrt{18}+y\right| - \ln\left|\sqrt{18}-y\right|\right) - 2y + C$

$= \displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+y}{\sqrt{18}-y}\right| - 2y + C$

$= \boxed{\displaystyle \sqrt{18} \ln\left|\frac{\sqrt{18}+\sqrt{9+x}}{\sqrt{18}-\sqrt{9+x}}\right| - 2\sqrt{9+x} + C}$

6 0

2 years ago

Select true statement

Ilia_Sergeevich [38]

Answer:

Both are true.

Step-by-step explanation:

A absolute always has a positive answer no matter what.

4 0

3 years ago

Read 2 more answers

The snow at my aunt winter house is up to 11/12 feet. A new storm added 7/2 feet what is the snow level now?

FinnZ [79.3K]

First make common denominators.

Multiply 6 to numerator and denominator of 7/2

7/2(6/6) = 42/12

Add the two fractions together.

42/12 + 11/12 = 53/12

Change the improper fraction into mixed fraction, and simplify if need be.

53/12 = 4 5/12

4 5/12 feet is your answer

hope this helps

6 0

2 years ago