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raketka [301]
3 years ago
6

Louis wants to carpet the rectangular floor of his basement. The basement has an area of 845. The width is 1/5 its length. What

is the length of Louis's basement?
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
I believe that it is like 640 But I'm wrong 
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A radio station requires DJs to play 3 commercials for every 18 songs they play. What is the unit rate of songs to commercials?
bulgar [2K]
6 songs

The way to find this answer is to divide 18 by 3, which is six, which means that after every six songs a commercial is played. 

Hope this was helpful and that I explained it correctly. 
3 0
3 years ago
If x,y and z are positive integers and 3x=4y=7z,
Pani-rosa [81]
<span>3x=4y=7z
so
GCF:
3 * 4 * 7 = 84

3x = 84 
  x = 28

4y = 84
  y = 21

7z = 84
  z = 12

</span><span>least possible value for
</span><span>x + y + z = 28 + 21 + 12 = 61
</span>
answer
(d) 61
5 0
3 years ago
Please look at the attached image. Really need Help!! Who ever find answer first will get brainily.
nadya68 [22]

Answer:

27°

Step-by-step explanation:

XWY and VWY are supplementary

∴ XWY + VWY = 180°

∴ XWY = 180° - VWY

XYW and ZYW are supplementary

∴ XYW + ZYW = 180°

∴ XYW = 180° - ZYW

ΔXWY is a right triangle at X

∴ XWY + XYW = 90°

∴ 180° - VWY + 180° - ZYW = 90°

∴ 180° - 6x + 180° - 4x = 90°

∴ 360° - 10x = 90°

∴ 10x = 270°

∴ x = 27°

7 0
3 years ago
Read 2 more answers
fancy goldfish x cost $3 each and common goldfish y cost $1 Graph tje function y=20-3x determine how many of each type of goldfi
NemiM [27]
6 Fancy, and 20 Common
4 0
3 years ago
A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.
kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis

4 0
3 years ago
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