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monitta
3 years ago
7

I am not sure how to do number 10?

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0
<span>the product lies between 3 *3/4</span>
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What is the distance between R(5,2) and S(4,-7)?<br><br> Round to the nearest tenth.
Naddik [55]
You can calculate the distance between two point using this fomula: 

√(x_2-x_1)^2+(y_2-y_1)^2


If you insert you values you get:

 √(4-5)^2+(-7-2)^2 = 9.06 = 9.1
5 0
3 years ago
What shape do degree 3 functions have?
weqwewe [10]

Answer: Third degree polynomials are also known as cubic polynomials. Cubics have these characteristics: One to three roots. Two or zero extrema.

HOPE THIS HELPS

Please brainliest

5 0
2 years ago
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It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help​
labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

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27-8/19

convert element to fraction

(27*19)/19-8/19

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(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

5 0
3 years ago
What is the difference of 56.45 and 49.26
vodomira [7]

Answer:

7.19

Step-by-step explanation:

  56.45

-  49.26

--------------

   07.19

6 0
3 years ago
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Find the coordinates of the point three tenths<br><br> of the way from A(-4, -8) to B(11, 7)
Leviafan [203]

let's first off take a peek at those values.

let's say the point with those coordinates is point C, so C is 3/10 of the way from A to B.

meaning, we take the segment AB and cut it in 10 equal pieces, AC takes 3 pieces, and CB takes 7 pieces, namely AC and CB are at a 3:7 ratio.


\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-4,-8)\qquad B(11,7)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{3:7}&#10;\\\\\\&#10;\cfrac{A\underline{C}}{\underline{C} B} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(-4,-8)=3(11,7)\\\\[-0.35em]&#10;~\dotfill\\\\&#10;C=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em]&#10;~\dotfill


\bf C=\left(\cfrac{(7\cdot -4)+(3\cdot 11)}{3+7}\quad ,\quad \cfrac{(7\cdot -8)+(3\cdot 7)}{3+7}\right)&#10;\\\\\\&#10;C=\left( \cfrac{-28+33}{10}~~,~~\cfrac{-56+21}{10} \right)\implies C=\left( \cfrac{5}{10}~~,~~\cfrac{-35}{10} \right)&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;~\hfill C=\left( \frac{1}{2}~,~-\frac{7}{2} \right)~\hfill

4 0
3 years ago
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