Option D:
A = 1, B = –3 and C = 4.
Solution:
Given equation is x – 3y + 4 =0.
General equation of a line format:
<em>Ax + By + C = 0</em>
<u>To identify A, B and C in the given equation:</u>
x – 3y + 4 =0 is a equation of a line which is in the form of Ax + By + C = 0.
That is,
The coefficient of x is A ⇒ A = 1
The coefficient of y is B ⇒ B = –3
The constant term is C ⇒ C = 4
A = 1, B = –3 and C = 4.
Hence Option D is the correct answer.
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Answer:
10
Step-by-step explanation:
Answer:
Step-by-step explanation:
A. the rate in which people fill up the hall in the first for minutes is 12
B. 95 people
C. the rate in which people fill up the hall between 10 and 15 minutes is 19
D. it was greater
Answer:
D
Step-by-step explanation:
BD is a mid- line segment and is one half the length of AE, that is
BD = 0.5 × 21 = 10.5 → d
