Answer:
def isAnagram(s1, s2):
list1=s1
list2=s2
sortedlist1 = sorted(list1)
sortedlist2 = sorted(list2)
if sortedlist1 == sortedlist2:
print(list1+ " and "+list2+ " are anagram")
else:
print(list1+ " and "+list2+ " are not anagram")
Explanation:
Here is a call to the function isAnagram():
list1 =input("Enter String1 ")
list1 =input("Enter String2 ")
isAnagram(list1,list2)
Attached is the run and output for this program
I will hope this helps :p
Answer:
The output of the given code as follows:
Output:
Area is: 12.60676
Explanation:
In the given code some information is missing so, the correct code to this question can be described as follows:
Program:
public class Test //defining class
{
public static void main(String[] args)//defining the main method
{
double radius= 2; //defining double variable radius
final double PI= 3.15169; //defining double variable PI
double area = radius * radius * PI; //defining double variable area that calculates values
System.out.println("Area is: " + area); //print values
}
}
Explanation:
- In the given java code a class "Test" is defined, in which a double variable "radius" is defined, which holds a value, that is 2.
- In the next step, a double constant variable, that is PI is defined, that holds a value, that is "3.15169".
- Then another double variable area is defined, that calculates the area value, and prints its value.
Answer:
(d) if (radius > 0) System.out.println(radius * radius * 3.14159);
Explanation:
Given
Code segment (a) to (d)
Required
Which is correct
Code segment (a): radius <=0
This means that radius is 0 or less, i.e. 0 or negative
Code segment (b): radius !=0
This means that radius is not equal to 0 i.e. it could be positive or negative but definitely not 0
Code segment (c): radius >=0
This means that radius is 0 or greater, i.e. 0 or positive
Code segment (d): radius >0
This means that radius is greater than 0 i.e. positive
<em>Hence, (d) is correct</em>
