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lukranit [14]
4 years ago
5

The five terms of the sequence described by recursive function

Mathematics
1 answer:
Phoenix [80]4 years ago
4 0

22, 76, 238, 724, 2182

to generate the terms substitute n = 0, 1, 2, 3, 4 into the recursive function

a_{1} = 3a_{0} + 10 = ( 3 × 4 ) + 10 = 22

a_{2} = 3a_{1} + 10 = (3 × 22)+ 10 = 76

a_{3} = 3a_{2} + 10 = ( 3× 76) + 10 = 238

a_{4} = 3a_{3} + 10 = ( 3 × 238) + 10 = 724

a_{5} = 3a_{4} + 10 = (3 × 724) + 10 = 2182


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55 points see attachment below
Ludmilka [50]

Answer:

  f(3) = -20

Step-by-step explanation:

To find the value of a function, substitute the number for the variable and do the arithmetic.

  f(x) = -2x^2 +x -5 . . . . . . given

  f(3) = -2(3^2) +(3) -5 . . . . function value for x = 3

  f(3) = -2(9) +3 -5 = -18 +3 -5

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Read 2 more answers
X-2y+z=5 <br>3x+3y-2z=-6 <br>2x-y+3z=11 <br>find x+y+z
BartSMP [9]
      x - 2y + z = 5   | *2
 ⇒ 2x - 4y+ 2z=10
     3x + 3y - 2z = - 6     } I sum up these relations
--------------------------------
    2x+3x - 4y+3y+2z-2z=10-6
     5x - y = 4       (1)

    3x + 3y - 2z = - 6   | *3         ⇒ 9x + 9y - 6z = - 18
    2x - y + 3z = 11     | *2         ⇒ 4x - 2y + 6z= 22       I sum up these
                                              ----------------------------------
                                                ⇒ 9x+4x+9y-2y-6z+6z= 4
                                                     13x+ 7y= 4     (2)
I write (1) and (2)
5x - y = 4   | *7
35x - 7y= 28
13x+7y=4
48x = 32
x= 32/48=4/6 ( 32:8=4, 48:8=6)
x= 2/3
5x-y=4, 
5*2/3-y=4
y=10/3 -4=10/3-12/3=-2/3
⇒ y= - 2/3
x - 2y + z = 5
2/3 - 2*(-2/3)+z=5
2/3+4/3+z=5
6/3+z=5
2+z=5
z=3
x+y+z=2/3-2/3+3=3

x+y+z=3







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