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nasty-shy [4]
3 years ago
13

Hüseyin draws a fox with a scale of 3 units on his graph paper represents 15cm. The fox has an actual height of 80cm. What is th

e height, in units, of the fox in Hüseyin's drawing?
Mathematics
2 answers:
Over [174]3 years ago
6 0

Answer:

The height of the fox in Huseyin's drawing is, 16 units

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

As per the statement: Huseyin draws a fox with a scale of 3 units on his graph paper represents 15 cm. The fox has an actual height of 80 cm.

⇒ We are given Scale of 3 units.

On graph paper the length of fox is 15 cm.

The fox has an actual height = 80 cm

let x be the height in units of the fox in Huseyin's drawing.

By definition of proportion;

\frac{3}{15} = \frac{x}{80}

by cross multiply we get;

3 \times 80 = 15x

Simplify:

240 = 15x

Divide both sides by 15 we get;

x = 16 units.

Therefore, the height of the fox in Huseyin's drawing is, 16 units


Anastasy [175]3 years ago
6 0

Answer:

16 units

Step-by-step explanation:

khan academy

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Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

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