2 years ago

NEED HELP ASAP!!

Mathematics

1 answer:

Ksju [112]2 years ago

7 0

Answer:

i) 2x² + 4x + 7x + 14

= 2x² + 11x + 14

ii) 2x² - 5x - 12x + 30

= 2x² - 17x + 30

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Help please? Im so lost...

posledela

Answer:

d. 89 degrees

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4 0

2 years ago

Evaluate the expression when p=-5 and q=10. 20+2q÷p

levacccp [35]

Answer:

-6

Step-by-step explanation:

p=-5 q=10

20+2q/p

10+2(10)/-5

10+20/-5

30/-5

-6

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2 years ago

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3 years ago

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Ivanshal [37]

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Step-by-step explanation:

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2 years ago

The complex number w is given by w= p-4i/2-3i where p is a real constant. Express w in the form a+bi where a and b are real cons

crimeas [40]

Step 1

Given;

$w=\frac{p-4i}{2-3i}$

Required; To express w in the form of a+bi.

Step 2

Express w in the form of a+bi

Multiply the numerator and the denominator by the binomial conjugate of (2-3i)

The binomial conjugate of (2-3i) = (2+3i)

$w=(\frac{p-4i}{2-3i})\times(\frac{2+3i}{2+3i})=\frac{2p+3pi-8i-12i^2}{4+6i-6i-9i^2}$ $\begin{gathered} w=\frac{2p+3pi-8i-12(-1)}{4-9(-1)} \\ \text{Note; i}^2=(\sqrt[]{-1})^2=-1 \end{gathered}$ $\begin{gathered} w=\frac{2p+3pi-8i+12}{4+9}=\frac{2p+3pi-8i+12}{13} \\ w=\frac{(2p+12)+(3p-8)i}{13} \\ w=\frac{(2p+12)}{13}+\frac{(3p-8)i}{13} \\ w=\frac{2(p+6)}{13}+\frac{(3p-8)i}{13} \end{gathered}$

where;

$\begin{gathered} a=\frac{2(p+6)}{13}_{} \\ bi=\frac{(3p-8)i}{13} \end{gathered}$

5 0

11 months ago