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3 years ago

Who distributes IP Address?

Computers and Technology

1 answer:

adoni [48]3 years ago

6 0

Answer:

The IP address is the internet protocol address that is basically assign to every device that is particularly connected to the network of the computer. The internet protocol is basically useful for the communication.

The main function of the IP address is that:

Used in the location addressing
For the network and host interface identification.

The IP address is basically distributed by the IANA ( Internet assigned number authority) and the main responsibility of the internet protocol is to distribute the IP address with the help of the RIR (Regional internet registries).

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_____ is a web application server that provides the ability to connect web servers to multiple data sources.

o-na [289]

ColdFusion/JRun is a web application server that provides the ability to connect web servers to multiple data sources.ColdFusion/JRun is an application server developed by Adobe, that is based on Sun Microsystems' Java 2 Platform, Enterprise Edition (J2EE). The other options are eliminated because: Ms Access is Database Management System , FoxPro is database development system and dBase is also data management system.

7 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e

Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = $0.184*56$ $= 10.304 kbps.$

Then, the outputs of the wach stations is $1000-bit frames/100 sec$

$\therefore$ , the output of the bits/ sec by each stations = $\frac{1000}{100} bits/sec = 10 bits/sec$

So, The output of the N stations is 10 bits/sec on the channel that having $10.304kb/sec$

Finally, N = $\frac{(10.304 \times 10^{3})}{10} = 1030 stations$

3 0

3 years ago

The _____ feature automatically corrects typing, spelling, capitalization, or grammar errors as you type them.

Snezhnost [94]

Autocorrect is the answer

6 0

3 years ago

Consider the graph of the function f(x) = 2(x + 3)2 + 2. Over which interval is the graph decreasing? (–∞, –3) (–∞, 2) (–3, ∞) (

Vaselesa [24]

Answer:

The interval over which the graph is decreasing is;

(-∞, -3)

Explanation:

The given function is f(x) = 2·(x + 3)² + 2

By expanding the function, we have;

2·x² + 12·x + 20

From the characteristics of a quadratic equation, we have;

The shape of a quadratic equation = A parabola

The coefficient of x² = +2 (positive), therefore the parabola opens up

The parabola has a minimum point

Points to the left of the minimum point are decreasing

The minimum point is obtained as the x-coordinate value when f'(x) = 0

∴ f'(x) = d(2·x² + 12·x + 20)/dx = 4·x + 12

At the minimum point, f'(x) = 4·x + 12 = 0

∴ x = -12/4 = -3

Therefore;

The graph is decreasing over the interval from -infinity (-∞) to -3 which is (-∞, -3)

Please find attached the graph of the function created with Microsoft Excel

The graph is decreasing over the interval (-∞, -3).

6 0

3 years ago

Read 2 more answers