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KIM [24]
3 years ago
12

Evaluate the function f(x) at the given numbers (correct to six decimal places). f(x) = x2 − 9x x2 − 8x − 9 , x = 0, −0.5, −0.9,

−0.95, −0.99, −0.999, −2, −1.5, −1.1, −1.01, −1.001

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

Answer:

See the attachment. (All results are integers, so are correct to 6 decimal places.)

Step-by-step explanation:

The function simplifies to ...

... f(x) = x(x-9)/((x+1)(x-9))

... f(x) = x/(x+1) . . . for x ≠ 9

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How to solve x^2+15x+44 with the magic x
Goshia [24]

Answer:

(x+4)(x+11)

Step-by-step explanation:

x^2+15x+44 is known as a simple quadratic. It is considered "simple" because x^2 is not greater than 1.

To solve quadratics, you need to factorise them (put them into brackets). You can do this by seeing what 2 numbers multiply to give 44, and add to give 15. I have attached a photograph of me breaking down the number 44 into its multiplying factors, and identifying which factors have the sum of 15.

You can see that I have got the numbers 4 and 11.

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The two brackets that I have got are (x+4)(x+11), and it doesn't matter which way around you write it.

6 0
2 years ago
75+45+x/69=180 <br> solve for x please :)
monitta

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Step-by-step explanation:

5 0
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ASAP PLEASE ......................
jonny [76]
Awnser 3 is the right one
4 0
3 years ago
Write the solution in interval notation: 4v+2&gt;-2 or 3v-5&lt;7
kari74 [83]

For this case we must find the solution of the following inequalities:

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From the first inequality we have:

4v + 2> -2

Subtracting 2 from both sides of the inequality:

4v> -2-2

Equal signs are added and the same sign is placed.

4v> -4

Dividing between 4 on both sides of the inequality:

v> \frac {-4} {4}\\v> -1

Thus, the solution is given by all values of "v" greater than -1.

From the second inequality we have:

3v-5

Adding 5 to both sides of the inequality we have:

3v

Dividing by 3 to both sides of the inequality we have:

v

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Then, the solution set is given by the union of both intervals.

The union consists of all the elements that are contained in each interval.

(-∞,∞)

Answer:

The solution set is: (-∞,∞)

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I'd go with Checking account B because its cheaper .


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