All categories

3 years ago

How do you solve equations that contain multiplication or division

1 answer:

6 0

Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.

Hopefully I solved your problem! :)

You might be interested in

Round the number to the place indicated.<br> Round to the nearest tenth: 1.4511

Evgen [1.6K]

1.500 since 45 rounds to 50

8 0

3 years ago

Which describes the correct way to convert minutes to hours? Divide the number of minutes by 24 Multiply the number of minutes b

fenix001 [56]

Answer:

divide the number of minutes to hours

8 0

3 years ago

I WILL MARK BRAINLIST!!

Soloha48 [4]

Answer:

For $(2x^2 + 8x - 8)$ , the group is CLOSED as it a polynomial.

Step-by-step explanation:

Here, the given polynomials are:

$P(x)=(5x^2+2x-6)\\Q(x)=(3x^2-6x+2)$

Now, a group G is said to be <u>CLOSED UNDER SUBTRACTION</u> if,

a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G

Now, here:

$R(x) = P(x) - Q(x) = (5x^2+2x-6) - (3x^2-6x+2) = (2x^2 + 8x - 8)$

or, $R(x) = (2x^2 + 8x - 8)$

Also, R(x) is a POLYNOMIAL.

So, R(x) is an Element of group G.

So, the set G of polynomials.

Hence, for the polynomial $(2x^2 + 8x - 8)$ , it will be a polynomial the group is CLOSED.

3 0

3 years ago

Read 2 more answers

Help with math and tell me how you for the answer<br>

slavikrds [6]

The answer is 8, first you convert 16 1/8 into a decimal and that is 16.125 and then you divide 129 by 16.125 :)

4 0

2 years ago

Help me please thank you

Harman [31]

$Answer: \\ j(m) = {2}^{m - 1} \Rightarrow j(4) = {2}^{4 - 1} = {2}^{3} = 8$

6 0

3 years ago