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4 years ago

What is the value of the x variable in the solution to the following system of equations?

Mathematics

1 answer:

Harlamova29_29 [7]4 years ago

8 0

Answer:

The correct answer is C.

Step-by-step explanation:

4x + 2y = 12

4(3) + 2(0) = 12

12 + 0 = 12

12 = 12

Hope this helps!

~Starr

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What percent of 120 is 20?

Aneli [31]

Answer:

16.67

Step-by-step explanation:

Step 1: We make the assumption that 20 is 100% since it is our output value.

Step 2: We next represent the value we seek with x.

Step 3: From step 1, it follows that 100%=20.

Step 4: In the same vein.

Step 5: This gives us a pair of simple equations

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

Step 7: Taking the inverse (or reciprocal) of both sides yields

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3 years ago

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How do you solve an inequality like this/ x-2/x+16 ≥ 0

neonofarm [45]

$\bf \cfrac{x-2}{x+16}\ge 0\implies \stackrel{cross-multiplying}{x-2\ge (x+16)0}\implies x-2\ge 0\implies x\ge 2$

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3 years ago

If 3^2x+1= 3x+5, what is the value of x? 2 3 4 6

REY [17]

Answer:

x = 4

Step-by-step explanation:

Set the exponents equal to each other

$3^{2x+1}=3^{x+5}$

2x + 1 = x + 5

Subtract x from both sides

x + 1 = 5

Subtract one from both sides

x = 4

So, the value of x is equal to 4.

4 0

3 years ago

The Ratio of men to women in a certain factory is 3 to 4. There are 198 men. How many workers are there?

klemol [59]

So 3:4::198:?. 3 is to 198 as 4 is to ?. You're solving for ? so you want that on the top of the fraction. 4/3=?/198. Multiply both sides by 198. ?=(4/3)(198)=264 women. Then add the men. 264+198=462 workers.

Check your work. (462/7)*3=198 men.

4 0

3 years ago

Read 2 more answers

Find two unit vectors orthogonal to a=⟨−2,−4,−2⟩a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩b=⟨−3,5,2⟩ Enter your answer so that the first non-ze

Levart [38]

Answer:

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

Step-by-step explanation:

for a=⟨−2,−4,−2⟩ and b=⟨−3,5,2⟩

a vector orthogonal to a and b can be found through the vectorial product of a and b. Thus

c= a x b $c=\left[\begin{array}{ccc}i&j&k\\-2&-4&-2\\-3&5&2\end{array}\right] = \left[\begin{array}{ccc}-4&-2\\5&2\end{array}\right]*i+\left[\begin{array}{ccc}-2&-2\\-3&2\end{array}\right]*j+\left[\begin{array}{ccc}-2&-4\\-3&5\end{array}\right]*k = 2*i -10*j - 22*k$

then c₁=⟨2,−10,−22⟩ and c₂= - c₁= ⟨-2,10,22⟩ are orthogonal to a and b

the corresponding unit vectors are

u₁=c₁/|c₁| = ⟨2,−10,−22⟩ / √(2²+(−10)²+(−22)²) = ⟨2,−10,−22⟩/(14*√3) = ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

then u₂= - u₁= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

then the unit vectors are

u₁= ⟨1/(7*√3),−5/(7*√3) ,−11/(7*√3)⟩

u₂= ⟨-1/(7*√3),5/(7*√3) ,11/(7*√3)⟩

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4 years ago