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STatiana [176]
3 years ago
15

Eval

Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

2/3

Step-by-step explanation:

0.25/0.375=0.666666666666666666666667

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Stephanie is baking cookies for a party. The recipe calls for 3 cups of flour,
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Answer:

2 cups of milk, and 1 cup of chocolate chips. What percentage of

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5 0
3 years ago
If a muffin costs 7¢, how much will 3 muffins cost?​
Goshia [24]

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21 cents

Step-by-step explanation:

6 0
3 years ago
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Rachel weighed her two cats, Tiger and Mittens. Tiger weighed 10.91 pounds, and Mittens weighed 178.08 ounces. Which cat is heav
Dafna11 [192]

Answer:

answer is c

Step-by-step explanation:

178.08 oz = 11.13 lb

11.13-10.91 = 0.22 lb

4 0
2 years ago
HURRRRRRRRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Viefleur [7K]

Answer:

41*

Step-by-step explanation:

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Hope This Helps;)<3

6 0
3 years ago
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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
3 years ago
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