How many worksheets display in the excel window when you create a new blank workbook?

Which of the following is used to allocate memory for the instance variables of an object of a class?1. the reserved word public

kodGreya [7K]

Answer:

The correct answer to the following question will be 2. the operator new.

Explanation:

New operator is used to allocating the memory to the instance object.The new object can be created by using a "new" keyword in java .

Syntax of using 'new' operator is :

class_name object_name=new class_name() // it allocated the memory to the class

For Example :

ABC obj = new ABC;

Now, this time obj points to the object of the ABC class.

obj = new ABC ();

call the construction of ABC class

3 0

3 years ago

Which type of operation writes the file system structure to the disk?

n200080 [17]

Formatting<span> writes the file system structure to the disk.</span>

8 0

3 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0

3 years ago

Create five circles like the Olympic Rings. fill them with the colors given below

Eva8 [605]

Answer: testing

Explanation:

Testing an answer with multiple attachments

3 0

3 years ago

Write a program that first reads in the name of an input file and then reads the file using the csv.reader() method. The file co

DaniilM [7]

Answer:

Here is the Python code.

import csv

inputfile = input("Enter name of the file: ")

count = {}

with open(inputfile, 'r') as csvfile:

csvfile = csv.reader(csvfile)

for line in csvfile:

for words in line:

if words not in count.keys():

count[words] = 1

else:

count[words] + 1

print(count)

Explanation:

I will explain the code line by line.

import csv here the css is imported in order to read the file using csv.reader() method

inputfile = input("Enter name of the file: ") This statement takes the name of the input file from the user

count = {} this is basically a dictionary which will store the words in the file and the number of times each word appears in the file.

with open(inputfile, 'r') as csvfile: This statement opens the inputfile using open() method in read mode. This basically opens the input file as csv type

csvfile = csv.reader(csvfile) This statement uses csv.reader() method to read the csv file contents.

for line in csvfile: This outer for loop iterates through each line of the file

for words in line: This inner loop iterates through each word in the line

if words not in count.keys(): This if condition checks if the word is not in the dictionary already. The dictionary holds key value pair and keys() method returns a list of all the keys of dictionary

count[words] = 1 if the word is not present already then assign 1 to the count dictionary

co unt[words] + 1 if the word is already present in dictionary increment count of the words by 1. Suppose the input file contains the following words:

hello,cat,man,hey,dog,boy,Hello,man,cat,woman,dog,Cat,hey,boy

Then because of co unt[words] + 1 statement if the word appears more than once in the file, then it will not be counted. So the output will be:

{' cat': 1, ' man': 1, ' dog': 1, ' woman': 1, ' Hello': 1, ' hey': 1, ' boy': 1, 'hello': 1, ' Cat': 1}

But if you want the program to count those words also in the file that appear more than once, then change this co unt[words] + 1 statement to:

count[words] = count[words] + 1

So if the word is already present in the file its frequency is increased by 1 by incrementing 1 to the count[words]. This will produce the following output:

{' Cat': 1, ' cat': 2, ' boy': 2, ' woman': 1, ' dog': 2, ' hey': 2, ' man': 2, ' Hello': 1, 'hello': 1}

You can see that cat, boy, dog and hey appear twice in the file.

print(count) This statement prints the dictionary contents with words and their frequencies.

The program with its output is attached.

3 0

3 years ago