How do you solve 2h + 7 > 21

Mathematics

2 answers:

Mrrafil [7]2 years ago

8 0

$2h + 7 > 21\\
2h>14\\
h>7$

Jet001 [13]2 years ago

5 0

$2h > 21-7 = 2h > 14 = \frac{2h}{2} > \frac{14}{2} = h= 7$

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gtnhenbr [62]

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$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

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If $k=-\frac45$ , then

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Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$