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Leona [35]
4 years ago
5

The final free points for the day, -5×3÷(2-(-4)-3×(-3))?​

Mathematics
2 answers:
alekssr [168]4 years ago
7 0

Answer:

<h2>-1</h2>

Step-by-step explanation:

-5\times \:3\div \left(2-\left(-4\right)-3\times \left(-3\right)\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(2-\left(-4\right)-3\times \\\\\left(-3\right)\right)\::\quad 15\\\\=-5\times \:3\div \:15\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:-5\times \:3\div \:15\:\\\\:\quad -1\\

likoan [24]4 years ago
3 0

Answer:

-1

Step-by-step explanation:

● -5×3÷(2-(-4)-3×(-3))

Multiply -3 and -3 first (-3×(-3)=9

● -5×3 ÷(2-(-4)×9)

Multiply -5 and 3 (-3×5= -15)

● -15 ÷(2-(-4)+9)

2-(-4) is 2+4 wich is 6

● -15÷(6+9)

● -15÷15

● -1

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Answer:

Step-by-step explanation:

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The law of cosines establishes:

c ^ 2 = a ^ 2 + b ^ 2 - 2*a*b*cosC.

general guidelines:

The law of cosines is used to find the missing parts of an oblique triangle (not rectangle) when either the two-sided measurements and the included angle measure are known (SAS) or the lengths of the three sides (SSS) are known.


Law of the sines:


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\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

The law of the sines is the relation between the sides and angles of triangles not rectangles (obliques). It simply states that the ratio of the length of one side of a triangle to the sine of the angle opposite to that side is equal for all sides and angles in a given triangle.

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What is the equation of the line that passes through (-5, -1) and is parallel to the line y=4x-6?
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Hello : 
<span>the equation all lines passes through (-5, -1) is :
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if this line parallal </span><span>to the line y=4x-6 so : m= 4  (same slope )
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