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Vedmedyk [2.9K]
3 years ago
5

Which of the following equations represents the greatest value of x? Equation 1 Equation 2 Equation 3 Equation 4 x2 = 35 x3 = 64

x3 = 125 x2 = 38 Equation 1 Equation 2 Equation 3 Equation 4Which of the following equations represents the greatest value of x? Equation 1 Equation 2 Equation 3 Equation 4 x2 = 35 x3 = 64 x3 = 125 x2 = 38 Equation 1 Equation 2 Equation 3 Equation 4
Mathematics
2 answers:
ladessa [460]3 years ago
4 0

Answer:

The 4th equation should be it

Step-by-step explanation:

Yuri [45]3 years ago
3 0
<h3>Answer:</h3>

Equation 4

<h3>Explanation:</h3>

Each of these is easily solved for x. A calculator can be helpful.

  1. x = √35 ≈ 5.91
  2. x = ∛64 = 4
  3. x = ∛125 = 5
  4. x = √38 ≈ 6.16

The solution to equation 4 is the largest value.

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\displaystyle\\&#10;P(x)=3x^3-5x^2-14x-4\\\\&#10;D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\&#10;\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\&#10;3x^3-5x^2-14x-4=0\\\\&#10;

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\displaystyle\\&#10;3x^3-5x^2-14x-4=0\\&#10;~~~~~-5x^2 = x^2 - 6x^2\\&#10;~~~~~-14x =-2x-12x \\&#10;3x^3+x^2 - 6x^2-2x-12x-4=0\\&#10;x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\&#10;(3x+1)(x^2-2x -4)=0\\\\&#10;\text{Solve: } x^2-2x -4=0\\\\&#10;x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\&#10;x_1 =1+\sqrt{5}\\&#10;x_2 =1-\sqrt{5}\\&#10;\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



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3 years ago
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Answer:

Give me more information about this question in order to help you

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Answer:

A

Step-by-step explanation:

Given

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To complete the square

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x - 7 = ± \sqrt{49} = ± 7 ( add 7 to both sides )

x = 7 ± 7 , thus

x = 7 + 7 = 14 or x = 7 - 7 = 0

6 0
3 years ago
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